Mister Exam

Lang:

How do you 1/(y-y^2) in partial fractions?

You have entered [src]

  1   
------
     2
y - y

$$\frac{1}{- y^{2} + y}$$

1/(y - y^2)

Fraction decomposition [src]

1/y - 1/(-1 + y)

$$- \frac{1}{y - 1} + \frac{1}{y}$$

1     1   
- - ------
y   -1 + y

General simplification [src]

   -1     
----------
y*(-1 + y)

$$- \frac{1}{y \left(y - 1\right)}$$

-1/(y*(-1 + y))

Numerical answer [src]

1/(y - y^2)

1/(y - y^2)

Common denominator [src]

 -1   
------
 2    
y  - y

$$- \frac{1}{y^{2} - y}$$

-1/(y^2 - y)

Combinatorics [src]

   -1     
----------
y*(-1 + y)

$$- \frac{1}{y \left(y - 1\right)}$$

-1/(y*(-1 + y))

Combining rational expressions [src]

    1    
---------
y*(1 - y)

$$\frac{1}{y \left(1 - y\right)}$$

1/(y*(1 - y))