Mister Exam

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How to use it?
How do you in partial fractions?:
y/(y+3)+y/3+2/y
2*x/(x^2+1)-2*x*(x^2-1)/(x^2+1)^2
y*(y+((1/(x+(x^2+y^2)^(1/2))*(1+(2*x/(2*(x^2+y^2)^(1/2)))))))-(y/(x^2+y^2)^(1/2))
(10*x^3-15*a*x^2)/(21*a*x^3-14*x^4)
Factor polynomial:
x^2-x-y^2-y
c^2-9
x^2-25
x^2-16
Least common denominator:
z/4*(x-y)-2*z/x-y
(z-2)/(6*z+(z-2)*(z-2))+(6/(z*z*z-8))
y/(y+3)+y/3+2/y
(((y-y)/(3*y-3))+(1/(y-1)))/((y+1)/3)+(2/(y^2-1))
Factor squared:
-y^4+9*y^2-5
-y^4+9*y^2-3
y^4-y^2-6
-y^4+y^2+5
Integral of d{x}:
1/(y-y^2)
Identical expressions
one /(y-y^ two)
1 divide by (y minus y squared )
one divide by (y minus y to the power of two)
1/(y-y2)
1/y-y2
1/(y-y²)
1/(y-y to the power of 2)
1/y-y^2
1 divide by (y-y^2)
Similar expressions
1/(y+y^2)

How do you 1/(y-y^2) in partial fractions?

You have entered [src]

  1   
------
     2
y - y

$$\frac{1}{- y^{2} + y}$$

1/(y - y^2)

Fraction decomposition [src]

1/y - 1/(-1 + y)

$$- \frac{1}{y - 1} + \frac{1}{y}$$

1     1   
- - ------
y   -1 + y

General simplification [src]

   -1     
----------
y*(-1 + y)

$$- \frac{1}{y \left(y - 1\right)}$$

-1/(y*(-1 + y))

Numerical answer [src]

1/(y - y^2)

1/(y - y^2)

Common denominator [src]

 -1   
------
 2    
y  - y

$$- \frac{1}{y^{2} - y}$$

-1/(y^2 - y)

Combinatorics [src]

   -1     
----------
y*(-1 + y)

$$- \frac{1}{y \left(y - 1\right)}$$

-1/(y*(-1 + y))

Combining rational expressions [src]

    1    
---------
y*(1 - y)

$$\frac{1}{y \left(1 - y\right)}$$

1/(y*(1 - y))