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How do you (x^2-9)/(x-3) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
 2    
x  - 9
------
x - 3 
$$\frac{x^{2} - 9}{x - 3}$$
(x^2 - 9)/(x - 3)
Fraction decomposition [src]
3 + x
$$x + 3$$
3 + x
General simplification [src]
3 + x
$$x + 3$$
3 + x
Common denominator [src]
3 + x
$$x + 3$$
3 + x
Combinatorics [src]
3 + x
$$x + 3$$
3 + x
Numerical answer [src]
(-9.0 + x^2)/(-3.0 + x)
(-9.0 + x^2)/(-3.0 + x)