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How do you (1-x/(1+x))/(1+x)^3 in partial fractions?

An expression to simplify:

The solution

You have entered [src]
      x  
1 - -----
    1 + x
---------
        3
 (1 + x) 
$$\frac{- \frac{x}{x + 1} + 1}{\left(x + 1\right)^{3}}$$
(1 - x/(1 + x))/(1 + x)^3
General simplification [src]
   1    
--------
       4
(1 + x) 
$$\frac{1}{\left(x + 1\right)^{4}}$$
(1 + x)^(-4)
Fraction decomposition [src]
(1 + x)^(-4)
$$\frac{1}{\left(x + 1\right)^{4}}$$
   1    
--------
       4
(1 + x) 
Combinatorics [src]
   1    
--------
       4
(1 + x) 
$$\frac{1}{\left(x + 1\right)^{4}}$$
(1 + x)^(-4)
Numerical answer [src]
(1.0 - x/(1.0 + x))/(1.0 + x)^3
(1.0 - x/(1.0 + x))/(1.0 + x)^3
Rational denominator [src]
   1    
--------
       4
(1 + x) 
$$\frac{1}{\left(x + 1\right)^{4}}$$
(1 + x)^(-4)
Common denominator [src]
            1             
--------------------------
     4            3      2
1 + x  + 4*x + 4*x  + 6*x 
$$\frac{1}{x^{4} + 4 x^{3} + 6 x^{2} + 4 x + 1}$$
1/(1 + x^4 + 4*x + 4*x^3 + 6*x^2)
Combining rational expressions [src]
   1    
--------
       4
(1 + x) 
$$\frac{1}{\left(x + 1\right)^{4}}$$
(1 + x)^(-4)