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How do you (x^2-6)/(x-3)-x/(x-3) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
 2            
x  - 6     x  
------ - -----
x - 3    x - 3
$$- \frac{x}{x - 3} + \frac{x^{2} - 6}{x - 3}$$
(x^2 - 6)/(x - 3) - x/(x - 3)
Fraction decomposition [src]
2 + x
$$x + 2$$
2 + x
General simplification [src]
2 + x
$$x + 2$$
2 + x
Common denominator [src]
2 + x
$$x + 2$$
2 + x
Rational denominator [src]
      2    
-6 + x  - x
-----------
   -3 + x  
$$\frac{x^{2} - x - 6}{x - 3}$$
(-6 + x^2 - x)/(-3 + x)
Combinatorics [src]
2 + x
$$x + 2$$
2 + x
Numerical answer [src]
(-6.0 + x^2)/(-3.0 + x) - x/(-3.0 + x)
(-6.0 + x^2)/(-3.0 + x) - x/(-3.0 + x)
Combining rational expressions [src]
      2    
-6 + x  - x
-----------
   -3 + x  
$$\frac{x^{2} - x - 6}{x - 3}$$
(-6 + x^2 - x)/(-3 + x)