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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of -4*x*exp(-2*x)
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Integral of (4-x^2)^(1/2)
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Integral of 1/cos^2(x)
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Integral of 1/(1+sin(x))
- How do you in partial fractions?:
- 1/(y-y^2)
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Identical expressions
- one /(y-y^ two)
- 1 divide by (y minus y squared )
- one divide by (y minus y to the power of two)
- 1/(y-y2)
- 1/y-y2
- 1/(y-y²)
- 1/(y-y to the power of 2)
- 1/y-y^2
- 1 divide by (y-y^2)
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Similar expressions
- 1/(y+y^2)
Integral of 1/(y-y^2) dx
The solution
You have entered
[src]
1 / | | 1 | 1*------ dy | 2 | y - y | / 0
$$\int\limits_{0}^{1} 1 \cdot \frac{1}{- y^{2} + y}\, dy$$
Integral(1/(y - y^2), (y, 0, 1))
The answer (Indefinite)
[src]
/ | | 1 | 1*------ dy = C - log(-2 + 2*y) + log(2*y) | 2 | y - y | /
$$\int 1 \cdot \frac{1}{- y^{2} + y}\, dy = C + \log{\left(2 y \right)} - \log{\left(2 y - 2 \right)}$$
Use the examples entering the upper and lower limits of integration.