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Factor polynomial z^3+z^2/10-z/4-1/40

An expression to simplify:

The solution

You have entered [src]
      2         
 3   z    z   1 
z  + -- - - - --
     10   4   40
$$\left(- \frac{z}{4} + \left(z^{3} + \frac{z^{2}}{10}\right)\right) - \frac{1}{40}$$
z^3 + z^2/10 - z/4 - 1/40
Fraction decomposition [src]
-1/40 + z^3 - z/4 + z^2/10
$$z^{3} + \frac{z^{2}}{10} - \frac{z}{4} - \frac{1}{40}$$
                 2
  1     3   z   z 
- -- + z  - - + --
  40        4   10
General simplification [src]
                 2
  1     3   z   z 
- -- + z  - - + --
  40        4   10
$$z^{3} + \frac{z^{2}}{10} - \frac{z}{4} - \frac{1}{40}$$
-1/40 + z^3 - z/4 + z^2/10
Factorization [src]
(x + 1/2)*(x + 1/10)*(x - 1/2)
$$\left(x + \frac{1}{10}\right) \left(x + \frac{1}{2}\right) \left(x - \frac{1}{2}\right)$$
((x + 1/2)*(x + 1/10))*(x - 1/2)
Powers [src]
                 2
  1     3   z   z 
- -- + z  - - + --
  40        4   10
$$z^{3} + \frac{z^{2}}{10} - \frac{z}{4} - \frac{1}{40}$$
-1/40 + z^3 - z/4 + z^2/10
Numerical answer [src]
-0.025 + z^3 + 0.1*z^2 - 0.25*z
-0.025 + z^3 + 0.1*z^2 - 0.25*z
Combinatorics [src]
(1 + 2*z)*(1 + 10*z)*(-1 + 2*z)
-------------------------------
               40              
$$\frac{\left(2 z - 1\right) \left(2 z + 1\right) \left(10 z + 1\right)}{40}$$
(1 + 2*z)*(1 + 10*z)*(-1 + 2*z)/40
Rational denominator [src]
                   2         3
-40 - 400*z + 160*z  + 1600*z 
------------------------------
             1600             
$$\frac{1600 z^{3} + 160 z^{2} - 400 z - 40}{1600}$$
(-40 - 400*z + 160*z^2 + 1600*z^3)/1600
Common denominator [src]
                 2
  1     3   z   z 
- -- + z  - - + --
  40        4   10
$$z^{3} + \frac{z^{2}}{10} - \frac{z}{4} - \frac{1}{40}$$
-1/40 + z^3 - z/4 + z^2/10
Assemble expression [src]
                 2
  1     3   z   z 
- -- + z  - - + --
  40        4   10
$$z^{3} + \frac{z^{2}}{10} - \frac{z}{4} - \frac{1}{40}$$
-1/40 + z^3 - z/4 + z^2/10
Trigonometric part [src]
                 2
  1     3   z   z 
- -- + z  - - + --
  40        4   10
$$z^{3} + \frac{z^{2}}{10} - \frac{z}{4} - \frac{1}{40}$$
-1/40 + z^3 - z/4 + z^2/10
Combining rational expressions [src]
-1 + 2*z*(-5 + 2*z*(1 + 10*z))
------------------------------
              40              
$$\frac{2 z \left(2 z \left(10 z + 1\right) - 5\right) - 1}{40}$$
(-1 + 2*z*(-5 + 2*z*(1 + 10*z)))/40