Mister Exam

Derivative of y=tg(4x-2)

Function f() - derivative -N order at the point
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The graph:

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Piecewise:

The solution

You have entered [src]
tan(4*x - 2)
tan(4x2)\tan{\left(4 x - 2 \right)}
tan(4*x - 2)
Detail solution
  1. Rewrite the function to be differentiated:

    tan(4x2)=sin(4x2)cos(4x2)\tan{\left(4 x - 2 \right)} = \frac{\sin{\left(4 x - 2 \right)}}{\cos{\left(4 x - 2 \right)}}

  2. Apply the quotient rule, which is:

    ddxf(x)g(x)=f(x)ddxg(x)+g(x)ddxf(x)g2(x)\frac{d}{d x} \frac{f{\left(x \right)}}{g{\left(x \right)}} = \frac{- f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}}{g^{2}{\left(x \right)}}

    f(x)=sin(4x2)f{\left(x \right)} = \sin{\left(4 x - 2 \right)} and g(x)=cos(4x2)g{\left(x \right)} = \cos{\left(4 x - 2 \right)}.

    To find ddxf(x)\frac{d}{d x} f{\left(x \right)}:

    1. Let u=4x2u = 4 x - 2.

    2. The derivative of sine is cosine:

      ddusin(u)=cos(u)\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}

    3. Then, apply the chain rule. Multiply by ddx(4x2)\frac{d}{d x} \left(4 x - 2\right):

      1. Differentiate 4x24 x - 2 term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: xx goes to 11

          So, the result is: 44

        2. The derivative of the constant 2-2 is zero.

        The result is: 44

      The result of the chain rule is:

      4cos(4x2)4 \cos{\left(4 x - 2 \right)}

    To find ddxg(x)\frac{d}{d x} g{\left(x \right)}:

    1. Let u=4x2u = 4 x - 2.

    2. The derivative of cosine is negative sine:

      dducos(u)=sin(u)\frac{d}{d u} \cos{\left(u \right)} = - \sin{\left(u \right)}

    3. Then, apply the chain rule. Multiply by ddx(4x2)\frac{d}{d x} \left(4 x - 2\right):

      1. Differentiate 4x24 x - 2 term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: xx goes to 11

          So, the result is: 44

        2. The derivative of the constant 2-2 is zero.

        The result is: 44

      The result of the chain rule is:

      4sin(4x2)- 4 \sin{\left(4 x - 2 \right)}

    Now plug in to the quotient rule:

    4sin2(4x2)+4cos2(4x2)cos2(4x2)\frac{4 \sin^{2}{\left(4 x - 2 \right)} + 4 \cos^{2}{\left(4 x - 2 \right)}}{\cos^{2}{\left(4 x - 2 \right)}}

  3. Now simplify:

    4cos2(4x2)\frac{4}{\cos^{2}{\left(4 x - 2 \right)}}


The answer is:

4cos2(4x2)\frac{4}{\cos^{2}{\left(4 x - 2 \right)}}

The graph
02468-8-6-4-2-1010-2000020000
The first derivative [src]
         2         
4 + 4*tan (4*x - 2)
4tan2(4x2)+44 \tan^{2}{\left(4 x - 2 \right)} + 4
The second derivative [src]
   /       2              \                  
32*\1 + tan (2*(-1 + 2*x))/*tan(2*(-1 + 2*x))
32(tan2(2(2x1))+1)tan(2(2x1))32 \left(\tan^{2}{\left(2 \left(2 x - 1\right) \right)} + 1\right) \tan{\left(2 \left(2 x - 1\right) \right)}
The third derivative [src]
    /       2              \ /         2              \
128*\1 + tan (2*(-1 + 2*x))/*\1 + 3*tan (2*(-1 + 2*x))/
128(tan2(2(2x1))+1)(3tan2(2(2x1))+1)128 \left(\tan^{2}{\left(2 \left(2 x - 1\right) \right)} + 1\right) \left(3 \tan^{2}{\left(2 \left(2 x - 1\right) \right)} + 1\right)
The graph
Derivative of y=tg(4x-2)