Mister Exam

Derivative of y=tg(4x+2)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
tan(4*x + 2)
$$\tan{\left(4 x + 2 \right)}$$
tan(4*x + 2)
Detail solution
  1. Rewrite the function to be differentiated:

  2. Apply the quotient rule, which is:

    and .

    To find :

    1. Let .

    2. The derivative of sine is cosine:

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    To find :

    1. Let .

    2. The derivative of cosine is negative sine:

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    Now plug in to the quotient rule:

  3. Now simplify:


The answer is:

The graph
The first derivative [src]
         2         
4 + 4*tan (4*x + 2)
$$4 \tan^{2}{\left(4 x + 2 \right)} + 4$$
The second derivative [src]
   /       2             \                 
32*\1 + tan (2*(1 + 2*x))/*tan(2*(1 + 2*x))
$$32 \left(\tan^{2}{\left(2 \left(2 x + 1\right) \right)} + 1\right) \tan{\left(2 \left(2 x + 1\right) \right)}$$
The third derivative [src]
    /       2             \ /         2             \
128*\1 + tan (2*(1 + 2*x))/*\1 + 3*tan (2*(1 + 2*x))/
$$128 \left(\tan^{2}{\left(2 \left(2 x + 1\right) \right)} + 1\right) \left(3 \tan^{2}{\left(2 \left(2 x + 1\right) \right)} + 1\right)$$
The graph
Derivative of y=tg(4x+2)