Mister Exam

Derivative of -2tg4x-2ctg5t

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

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-2*tan(4*x) - 2*cot(5*t)
$$- 2 \tan{\left(4 x \right)} - 2 \cot{\left(5 t \right)}$$
-2*tan(4*x) - 2*cot(5*t)
Detail solution
  1. Differentiate term by term:

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Rewrite the function to be differentiated:

      2. Apply the quotient rule, which is:

        and .

        To find :

        1. Let .

        2. The derivative of sine is cosine:

        3. Then, apply the chain rule. Multiply by :

          1. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: goes to

            So, the result is:

          The result of the chain rule is:

        To find :

        1. Let .

        2. The derivative of cosine is negative sine:

        3. Then, apply the chain rule. Multiply by :

          1. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: goes to

            So, the result is:

          The result of the chain rule is:

        Now plug in to the quotient rule:

      So, the result is:

    2. The derivative of the constant is zero.

    The result is:

  2. Now simplify:


The answer is:

The first derivative [src]
          2     
-8 - 8*tan (4*x)
$$- 8 \tan^{2}{\left(4 x \right)} - 8$$
The second derivative [src]
    /       2     \         
-64*\1 + tan (4*x)/*tan(4*x)
$$- 64 \left(\tan^{2}{\left(4 x \right)} + 1\right) \tan{\left(4 x \right)}$$
The third derivative [src]
     /       2     \ /         2     \
-256*\1 + tan (4*x)/*\1 + 3*tan (4*x)/
$$- 256 \left(\tan^{2}{\left(4 x \right)} + 1\right) \left(3 \tan^{2}{\left(4 x \right)} + 1\right)$$