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Factor x^4-5*x^2+4 squared

An expression to simplify:

The solution

You have entered [src]
 4      2    
x  - 5*x  + 4
$$\left(x^{4} - 5 x^{2}\right) + 4$$
x^4 - 5*x^2 + 4
General simplification [src]
     4      2
4 + x  - 5*x 
$$x^{4} - 5 x^{2} + 4$$
4 + x^4 - 5*x^2
Factorization [src]
(x + 2)*(x + 1)*(x - 1)*(x - 2)
$$\left(x + 1\right) \left(x + 2\right) \left(x - 1\right) \left(x - 2\right)$$
(((x + 2)*(x + 1))*(x - 1))*(x - 2)
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{4} - 5 x^{2}\right) + 4$$
To do this, let's use the formula
$$a x^{4} + b x^{2} + c = a \left(m + x^{2}\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -5$$
$$c = 4$$
Then
$$m = - \frac{5}{2}$$
$$n = - \frac{9}{4}$$
So,
$$\left(x^{2} - \frac{5}{2}\right)^{2} - \frac{9}{4}$$
Assemble expression [src]
     4      2
4 + x  - 5*x 
$$x^{4} - 5 x^{2} + 4$$
4 + x^4 - 5*x^2
Combinatorics [src]
(1 + x)*(-1 + x)*(-2 + x)*(2 + x)
$$\left(x - 2\right) \left(x - 1\right) \left(x + 1\right) \left(x + 2\right)$$
(1 + x)*(-1 + x)*(-2 + x)*(2 + x)
Combining rational expressions [src]
     2 /      2\
4 + x *\-5 + x /
$$x^{2} \left(x^{2} - 5\right) + 4$$
4 + x^2*(-5 + x^2)
Common denominator [src]
     4      2
4 + x  - 5*x 
$$x^{4} - 5 x^{2} + 4$$
4 + x^4 - 5*x^2
Rational denominator [src]
     4      2
4 + x  - 5*x 
$$x^{4} - 5 x^{2} + 4$$
4 + x^4 - 5*x^2
Trigonometric part [src]
     4      2
4 + x  - 5*x 
$$x^{4} - 5 x^{2} + 4$$
4 + x^4 - 5*x^2
Numerical answer [src]
4.0 + x^4 - 5.0*x^2
4.0 + x^4 - 5.0*x^2
Powers [src]
     4      2
4 + x  - 5*x 
$$x^{4} - 5 x^{2} + 4$$
4 + x^4 - 5*x^2