Mister Exam
Other calculators
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How to use it?
- Factor polynomial:
- x^3-1
- x^7+1
- x^2-x+1
- m^2-n^2+m+n
- Least common denominator:
- z^(((p-3)/(p^2+3*p))/(12/(9-p^2))*(3/(3*p-p^2)))
- (z/c+c/z)/(z^2+c^2)/(5*z^9*c)
- (z/c-c/z)*5*z*c/(z+c)
- (z/b-b/z)*6*z*b/(z+b)
- Factor squared:
- y^4+y^2-1
- y^4+9*y^2-3
- y^4+9*y^2+3
- y^4+9*y^2+2
- How do you in partial fractions?:
- (((z^2)+(6*z+4))/((z^3)+8))/(1/-1)
- (a^2+a*b)/(a+b)
- x^3*y^12/(x*y^4)^3
- (x^2+x-6)/(x+2)
- Graphing y =:
- x^2-x+1
- Integral of d{x}:
- x^2-x+1
- Derivative of:
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x^2-x+1
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Identical expressions
- x^ two -x+ one
- x squared minus x plus 1
- x to the power of two minus x plus one
- x2-x+1
- x²-x+1
- x to the power of 2-x+1
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Similar expressions
- x^2-x-1
- x^2+x+1
Factor polynomial x^2-x+1
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} - x\right) + 1$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -1$$
$$c = 1$$
Then
$$m = - \frac{1}{2}$$
$$n = \frac{3}{4}$$
So,
$$\left(x - \frac{1}{2}\right)^{2} + \frac{3}{4}$$
$$\left(x^{2} - x\right) + 1$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -1$$
$$c = 1$$
Then
$$m = - \frac{1}{2}$$
$$n = \frac{3}{4}$$
So,
$$\left(x - \frac{1}{2}\right)^{2} + \frac{3}{4}$$
Factorization
[src]
/ ___\ / ___\ | 1 I*\/ 3 | | 1 I*\/ 3 | |x + - - + -------|*|x + - - - -------| \ 2 2 / \ 2 2 /
$$\left(x + \left(- \frac{1}{2} - \frac{\sqrt{3} i}{2}\right)\right) \left(x + \left(- \frac{1}{2} + \frac{\sqrt{3} i}{2}\right)\right)$$
(x - 1/2 + i*sqrt(3)/2)*(x - 1/2 - i*sqrt(3)/2)