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How to use it?
How do you in partial fractions?
:
(((z^2)+(6*z+4))/((z^3)+8))/(1/-1)
(a^2+a*b)/(a+b)
(x^2-6*x-9)/(x-3)
5*((x-4)/(x^2+4*x)-16/(16-x^2))/(1+4/x)
Factor polynomial
:
x^3-1
x^7+1
m^3-n^3
x^2+1^2
Least common denominator
:
z^(((p-3)/(p^2+3*p))/(12/(9-p^2))*(3/(3*p-p^2)))
(z/c+c/z)/(z^2+c^2)/(5*z^9*c)
(z/c-c/z)*5*z*c/(z+c)
(z/b-b/z)*6*z*b/(z+b)
Factor squared
:
y^4+y^2-1
y^4+9*y^2-6
-y^4+9*y^2-5
y^4-9*y^2-5
Identical expressions
(a^ two +a*b)/(a+b)
(a squared plus a multiply by b) divide by (a plus b)
(a to the power of two plus a multiply by b) divide by (a plus b)
(a2+a*b)/(a+b)
a2+a*b/a+b
(a²+a*b)/(a+b)
(a to the power of 2+a*b)/(a+b)
(a^2+ab)/(a+b)
(a2+ab)/(a+b)
a2+ab/a+b
a^2+ab/a+b
(a^2+a*b) divide by (a+b)
Similar expressions
(a^2-a*b)/(a+b)
(a^2+a*b)/(a-b)
Expression simplification
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Fraction Decomposition into the simple
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(a^2+a*b)/(a+b)
How do you (a^2+a*b)/(a+b) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
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2 a + a*b -------- a + b
$$\frac{a^{2} + a b}{a + b}$$
(a^2 + a*b)/(a + b)
Fraction decomposition
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a
$$a$$
a
General simplification
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a
$$a$$
a
Combinatorics
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a
$$a$$
a
Common denominator
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a
$$a$$
a
Combining rational expressions
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a
$$a$$
a
Numerical answer
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(a^2 + a*b)/(a + b)
(a^2 + a*b)/(a + b)