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How do you (x^2+x-6)/(x+2) in partial fractions?

You have entered [src]

 2        
x  + x - 6
----------
  x + 2

$$\frac{\left(x^{2} + x\right) - 6}{x + 2}$$

(x^2 + x - 6)/(x + 2)

General simplification [src]

          2
-6 + x + x 
-----------
   2 + x

$$\frac{x^{2} + x - 6}{x + 2}$$

(-6 + x + x^2)/(2 + x)

Fraction decomposition [src]

-1 + x - 4/(2 + x)

$$x - 1 - \frac{4}{x + 2}$$

           4  
-1 + x - -----
         2 + x

Numerical answer [src]

(-6.0 + x + x^2)/(2.0 + x)

(-6.0 + x + x^2)/(2.0 + x)

Powers [src]

          2
-6 + x + x 
-----------
   2 + x

$$\frac{x^{2} + x - 6}{x + 2}$$

(-6 + x + x^2)/(2 + x)

Common denominator [src]

           4  
-1 + x - -----
         2 + x

$$x - 1 - \frac{4}{x + 2}$$

-1 + x - 4/(2 + x)

Rational denominator [src]

          2
-6 + x + x 
-----------
   2 + x

$$\frac{x^{2} + x - 6}{x + 2}$$

(-6 + x + x^2)/(2 + x)

Assemble expression [src]

          2
-6 + x + x 
-----------
   2 + x

$$\frac{x^{2} + x - 6}{x + 2}$$

(-6 + x + x^2)/(2 + x)

Combinatorics [src]

(-2 + x)*(3 + x)
----------------
     2 + x

$$\frac{\left(x - 2\right) \left(x + 3\right)}{x + 2}$$

(-2 + x)*(3 + x)/(2 + x)

Combining rational expressions [src]

-6 + x*(1 + x)
--------------
    2 + x

$$\frac{x \left(x + 1\right) - 6}{x + 2}$$

(-6 + x*(1 + x))/(2 + x)

Trigonometric part [src]

          2
-6 + x + x 
-----------
   2 + x

$$\frac{x^{2} + x - 6}{x + 2}$$

(-6 + x + x^2)/(2 + x)