Mister Exam

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How do you in partial fractions?:
((z^2+1)^2/(4*z^2))/(13+12*((z^2+1)/2*z*z))
x^3*y^12/(x*y^4)^3
2*a*(3*a-p)/(2*p-6*a)
y/(y+3)+y/3+2/y
Factor polynomial:
x^2+x^2
c^2+c^2
x^2-x-y^2-y
c^2-9
Least common denominator:
((z*(a+w))/2)+((w*(a-z))/2)+((a-z)*a)
z-8/z^2/3*z^(1/3)+4
(z-6*z/z+3)/z-3/z+3
(z^5-5*z^3+10*z-10/z+5/z^3-1/z^5)*(z^3-3*z+3/z-1/z^3)
Factor squared:
-y^4+9*y^2+5
y^4+9*y^2+2
-y^4-9*y^2+15
-y^4+8*y^2-4
Identical expressions
x^ three *y^ twelve /(x*y^ four)^ three
x cubed multiply by y to the power of 12 divide by (x multiply by y to the power of 4) cubed
x to the power of three multiply by y to the power of twelve divide by (x multiply by y to the power of four) to the power of three
x3*y12/(x*y4)3
x3*y12/x*y43
x³*y^12/(x*y⁴)³
x to the power of 3*y to the power of 12/(x*y to the power of 4) to the power of 3
x^3y^12/(xy^4)^3
x3y12/(xy4)3
x3y12/xy43
x^3y^12/xy^4^3
x^3*y^12 divide by (x*y^4)^3

How do you x^3y^12/(xy^4)^3 in partial fractions?

You have entered [src]

  3  12
 x *y  
-------
      3
/   4\ 
\x*y /

$$\frac{x^{3} y^{12}}{\left(x y^{4}\right)^{3}}$$

(x^3*y^12)/(x*y^4)^3

Fraction decomposition [src]

$$1$$

General simplification [src]

$$1$$

Common denominator [src]

$$1$$

Expand expression [src]

$$1$$

Assemble expression [src]

$$1$$

Rational denominator [src]

$$1$$

Powers [src]

$$1$$

Combinatorics [src]

$$1$$

Trigonometric part [src]

$$1$$

Numerical answer [src]

1.00000000000000

1.00000000000000

Combining rational expressions [src]

$$1$$

How do you x^3*y^12/(x*y^4)^3 in partial fractions?