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How do you (x^2-x-6)/(x+2) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
 2        
x  - x - 6
----------
  x + 2   
$$\frac{\left(x^{2} - x\right) - 6}{x + 2}$$
(x^2 - x - 6)/(x + 2)
Fraction decomposition [src]
-3 + x
$$x - 3$$
-3 + x
General simplification [src]
-3 + x
$$x - 3$$
-3 + x
Assemble expression [src]
      2    
-6 + x  - x
-----------
   2 + x   
$$\frac{x^{2} - x - 6}{x + 2}$$
(-6 + x^2 - x)/(2 + x)
Common denominator [src]
-3 + x
$$x - 3$$
-3 + x
Trigonometric part [src]
      2    
-6 + x  - x
-----------
   2 + x   
$$\frac{x^{2} - x - 6}{x + 2}$$
(-6 + x^2 - x)/(2 + x)
Rational denominator [src]
      2    
-6 + x  - x
-----------
   2 + x   
$$\frac{x^{2} - x - 6}{x + 2}$$
(-6 + x^2 - x)/(2 + x)
Combining rational expressions [src]
-6 + x*(-1 + x)
---------------
     2 + x     
$$\frac{x \left(x - 1\right) - 6}{x + 2}$$
(-6 + x*(-1 + x))/(2 + x)
Combinatorics [src]
-3 + x
$$x - 3$$
-3 + x
Powers [src]
      2    
-6 + x  - x
-----------
   2 + x   
$$\frac{x^{2} - x - 6}{x + 2}$$
(-6 + x^2 - x)/(2 + x)
Numerical answer [src]
(-6.0 + x^2 - x)/(2.0 + x)
(-6.0 + x^2 - x)/(2.0 + x)