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How to use it?
How do you in partial fractions?
:
(z/c+c/z)/((z^2+c^2)/(5*z^9*c))
(x^2-9)/(x+3)
(x+5)/(x^2+22*x+85)
(x^2-x-12)/(x+3)
Factor polynomial
:
x^3-8
x^2+x-6
x^2+4
x^3+1
Least common denominator
:
-2*sqrt(3)/(3*sqrt(1-(2*x-1)^2/3))
2/(a+2)+(a-2)/(a^2+4*a+4)/(a/(2*a-4)+(a^2+4)/(8-2*a)-2/(2*a+a^2))
(z+z/q)*(z-z/q)
z/(z+9)^2-z/(z^2-81)
Factor squared
:
y^4+y^2+3
-y^4+y^2+14
y^4-y^2+15
y^4-y^2+3
Derivative of
:
(x^2-9)/(x+3)
Canonical form
:
(x^2-9)/(x+3)
Integral of d{x}
:
(x^2-9)/(x+3)
Identical expressions
(x^ two - nine)/(x+ three)
(x squared minus 9) divide by (x plus 3)
(x to the power of two minus nine) divide by (x plus three)
(x2-9)/(x+3)
x2-9/x+3
(x²-9)/(x+3)
(x to the power of 2-9)/(x+3)
x^2-9/x+3
(x^2-9) divide by (x+3)
Similar expressions
(x^2+9)/(x+3)
(x^2-9)/(x-3)
Expression simplification
/
Fraction Decomposition into the simple
/
(x^2-9)/(x+3)
How do you (x^2-9)/(x+3) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
2 x - 9 ------ x + 3
$$\frac{x^{2} - 9}{x + 3}$$
(x^2 - 9)/(x + 3)
Fraction decomposition
[src]
-3 + x
$$x - 3$$
-3 + x
General simplification
[src]
-3 + x
$$x - 3$$
-3 + x
Common denominator
[src]
-3 + x
$$x - 3$$
-3 + x
Combinatorics
[src]
-3 + x
$$x - 3$$
-3 + x
Numerical answer
[src]
(-9.0 + x^2)/(3.0 + x)
(-9.0 + x^2)/(3.0 + x)