Mister Exam
Factor y^4+y^2+3 squared
The solution
Factorization
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/ / / ____\\ / / ____\\\ / / / ____\\ / / ____\\\ / / / ____\\ / / ____\\\ / / / ____\\ / / ____\\\ | 4 ___ |atan\\/ 11 /| 4 ___ |atan\\/ 11 /|| | 4 ___ |atan\\/ 11 /| 4 ___ |atan\\/ 11 /|| | 4 ___ |atan\\/ 11 /| 4 ___ |atan\\/ 11 /|| | 4 ___ |atan\\/ 11 /| 4 ___ |atan\\/ 11 /|| |x + \/ 3 *sin|------------| + I*\/ 3 *cos|------------||*|x + \/ 3 *sin|------------| - I*\/ 3 *cos|------------||*|x + - \/ 3 *sin|------------| + I*\/ 3 *cos|------------||*|x + - \/ 3 *sin|------------| - I*\/ 3 *cos|------------|| \ \ 2 / \ 2 // \ \ 2 / \ 2 // \ \ 2 / \ 2 // \ \ 2 / \ 2 //
$$\left(x + \left(\sqrt[4]{3} \sin{\left(\frac{\operatorname{atan}{\left(\sqrt{11} \right)}}{2} \right)} - \sqrt[4]{3} i \cos{\left(\frac{\operatorname{atan}{\left(\sqrt{11} \right)}}{2} \right)}\right)\right) \left(x + \left(\sqrt[4]{3} \sin{\left(\frac{\operatorname{atan}{\left(\sqrt{11} \right)}}{2} \right)} + \sqrt[4]{3} i \cos{\left(\frac{\operatorname{atan}{\left(\sqrt{11} \right)}}{2} \right)}\right)\right) \left(x + \left(- \sqrt[4]{3} \sin{\left(\frac{\operatorname{atan}{\left(\sqrt{11} \right)}}{2} \right)} + \sqrt[4]{3} i \cos{\left(\frac{\operatorname{atan}{\left(\sqrt{11} \right)}}{2} \right)}\right)\right) \left(x + \left(- \sqrt[4]{3} \sin{\left(\frac{\operatorname{atan}{\left(\sqrt{11} \right)}}{2} \right)} - \sqrt[4]{3} i \cos{\left(\frac{\operatorname{atan}{\left(\sqrt{11} \right)}}{2} \right)}\right)\right)$$
(((x + 3^(1/4)*sin(atan(sqrt(11))/2) + i*3^(1/4)*cos(atan(sqrt(11))/2))*(x + 3^(1/4)*sin(atan(sqrt(11))/2) - i*3^(1/4)*cos(atan(sqrt(11))/2)))*(x - 3^(1/4)*sin(atan(sqrt(11))/2) + i*3^(1/4)*cos(atan(sqrt(11))/2)))*(x - 3^(1/4)*sin(atan(sqrt(11))/2) - i*3^(1/4)*cos(atan(sqrt(11))/2))
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(y^{4} + y^{2}\right) + 3$$
To do this, let's use the formula
$$a y^{4} + b y^{2} + c = a \left(m + y^{2}\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = 3$$
Then
$$m = \frac{1}{2}$$
$$n = \frac{11}{4}$$
So,
$$\left(y^{2} + \frac{1}{2}\right)^{2} + \frac{11}{4}$$
$$\left(y^{4} + y^{2}\right) + 3$$
To do this, let's use the formula
$$a y^{4} + b y^{2} + c = a \left(m + y^{2}\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = 3$$
Then
$$m = \frac{1}{2}$$
$$n = \frac{11}{4}$$
So,
$$\left(y^{2} + \frac{1}{2}\right)^{2} + \frac{11}{4}$$
Combining rational expressions
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2 / 2\ 3 + y *\1 + y /
$$y^{2} \left(y^{2} + 1\right) + 3$$
3 + y^2*(1 + y^2)