Mister Exam

Lang:

How to use it?
How do you in partial fractions?:
(z/c+c/z)/((z^2+c^2)/(5*z^9*c))
(x^2-9)/(x+3)
(x+5)/(x^2+22*x+85)
(x^2-x-12)/(x+3)
Factor polynomial:
x^3-8
x^2+x-6
x^2+4
x^3+1
Least common denominator:
-2*sqrt(3)/(3*sqrt(1-(2*x-1)^2/3))
2/(a+2)+(a-2)/(a^2+4*a+4)/(a/(2*a-4)+(a^2+4)/(8-2*a)-2/(2*a+a^2))
(z+z/q)*(z-z/q)
z/(z+9)^2-z/(z^2-81)
Factor squared:
y^4+y^2+3
-y^4+y^2+14
y^4-y^2+15
y^4-y^2+3
Least common denominator:
(z/c+c/z)/((z^2+c^2)/(5*z^9*c))
Identical expressions
(z/c+c/z)/((z^ two +c^ two)/(five *z^ nine *c))
(z divide by c plus c divide by z) divide by ((z squared plus c squared ) divide by (5 multiply by z to the power of 9 multiply by c))
(z divide by c plus c divide by z) divide by ((z to the power of two plus c to the power of two) divide by (five multiply by z to the power of nine multiply by c))
(z/c+c/z)/((z2+c2)/(5*z9*c))
z/c+c/z/z2+c2/5*z9*c
(z/c+c/z)/((z²+c²)/(5*z⁹*c))
(z/c+c/z)/((z to the power of 2+c to the power of 2)/(5*z to the power of 9*c))
(z/c+c/z)/((z^2+c^2)/(5z^9c))
(z/c+c/z)/((z2+c2)/(5z9c))
z/c+c/z/z2+c2/5z9c
z/c+c/z/z^2+c^2/5z^9c
(z divide by c+c divide by z) divide by ((z^2+c^2) divide by (5*z^9*c))
Similar expressions
(z/c-c/z)/((z^2+c^2)/(5*z^9*c))
(z/c+c/z)/((z^2-c^2)/(5*z^9*c))

How do you (z/c+c/z)/((z^2+c^2)/(5z^9c)) in partial fractions?

You have entered [src]

  z   c  
  - + -  
  c   z  
---------
/ 2    2\
|z  + c |
|-------|
|    9  |
\ 5*z *c/

$$\frac{\frac{c}{z} + \frac{z}{c}}{\frac{1}{c 5 z^{9}} \left(c^{2} + z^{2}\right)}$$

(z/c + c/z)/(((z^2 + c^2)/(((5*z^9)*c))))

General simplification [src]

   8
5*z

$$5 z^{8}$$

5*z^8

Fraction decomposition [src]

5*z^8

$$5 z^{8}$$

   8
5*z

Expand expression [src]

     9 /z   c\
5*c*z *|- + -|
       \c   z/
--------------
    2    2    
   z  + c

$$\frac{5 c z^{9} \left(\frac{c}{z} + \frac{z}{c}\right)}{c^{2} + z^{2}}$$

5*c*z^9*(z/c + c/z)/(z^2 + c^2)

Assemble expression [src]

     9 /c   z\
5*c*z *|- + -|
       \z   c/
--------------
    2    2    
   c  + z

$$\frac{5 c z^{9} \left(\frac{c}{z} + \frac{z}{c}\right)}{c^{2} + z^{2}}$$

5*c*z^9*(c/z + z/c)/(c^2 + z^2)

Trigonometric part [src]

     9 /c   z\
5*c*z *|- + -|
       \z   c/
--------------
    2    2    
   c  + z

$$\frac{5 c z^{9} \left(\frac{c}{z} + \frac{z}{c}\right)}{c^{2} + z^{2}}$$

5*c*z^9*(c/z + z/c)/(c^2 + z^2)

Common denominator [src]

   8
5*z

$$5 z^{8}$$

5*z^8

Powers [src]

     9 /c   z\
5*c*z *|- + -|
       \z   c/
--------------
    2    2    
   c  + z

$$\frac{5 c z^{9} \left(\frac{c}{z} + \frac{z}{c}\right)}{c^{2} + z^{2}}$$

   9 /c   z\
c*z *|- + -|
     \z   c/
------------
   2    2   
  c    z    
  -- + --   
  5    5

$$\frac{c z^{9} \left(\frac{c}{z} + \frac{z}{c}\right)}{\frac{c^{2}}{5} + \frac{z^{2}}{5}}$$

c*z^9*(c/z + z/c)/(c^2/5 + z^2/5)

Rational denominator [src]

   8
5*z

$$5 z^{8}$$

5*z^8

Combining rational expressions [src]

   8
5*z

$$5 z^{8}$$

5*z^8

Numerical answer [src]

5.0*c*z^9*(c/z + z/c)/(c^2 + z^2)

5.0*c*z^9*(c/z + z/c)/(c^2 + z^2)

Combinatorics [src]

   8
5*z

$$5 z^{8}$$

5*z^8

How do you (z/c+c/z)/((z^2+c^2)/(5*z^9*c)) in partial fractions?