Integral of log(sin(x)) dx
The solution
Detail solution
-
Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=log(sin(x)) and let dv(x)=1.
Then du(x)=sin(x)cos(x).
To find v(x):
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
Now evaluate the sub-integral.
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Don't know the steps in finding this integral.
But the integral is
∫sin(x)xcos(x)dx
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Now simplify:
xlog(sin(x))−∫tan(x)xdx
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Add the constant of integration:
xlog(sin(x))−∫tan(x)xdx+constant
The answer is:
xlog(sin(x))−∫tan(x)xdx+constant
The answer (Indefinite)
[src]
/
/ |
| | x*cos(x)
| log(sin(x)) dx = C - | -------- dx + x*log(sin(x))
| | sin(x)
/ |
/
∫log(sin(x))dx=C+xlog(sin(x))−∫sin(x)xcos(x)dx
pi
--
2
/
|
| log(sin(x)) dx
|
/
0
0∫2πlog(sin(x))dx
=
pi
--
2
/
|
| log(sin(x)) dx
|
/
0
0∫2πlog(sin(x))dx
Integral(log(sin(x)), (x, 0, pi/2))
Use the examples entering the upper and lower limits of integration.