Integral of log(sin(x)^3) dx
The solution
Detail solution
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Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=log(sin3(x)) and let dv(x)=1.
Then du(x)=sin(x)3cos(x).
To find v(x):
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
Now evaluate the sub-integral.
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The integral of a constant times a function is the constant times the integral of the function:
∫sin(x)3xcos(x)dx=3∫sin(x)xcos(x)dx
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Don't know the steps in finding this integral.
But the integral is
∫sin(x)xcos(x)dx
So, the result is: 3∫sin(x)xcos(x)dx
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Now simplify:
xlog(sin3(x))−3∫tan(x)xdx
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Add the constant of integration:
xlog(sin3(x))−3∫tan(x)xdx+constant
The answer is:
xlog(sin3(x))−3∫tan(x)xdx+constant
The answer (Indefinite)
[src]
/ /
| |
| / 3 \ | x*cos(x) / 3 \
| log\sin (x)/ dx = C - 3* | -------- dx + x*log\sin (x)/
| | sin(x)
/ |
/
∫log(sin3(x))dx=C+xlog(sin3(x))−3∫sin(x)xcos(x)dx
1
/
|
| / 3 \
| log\sin (x)/ dx
|
/
0
0∫1log(sin3(x))dx
=
1
/
|
| / 3 \
| log\sin (x)/ dx
|
/
0
0∫1log(sin3(x))dx
Integral(log(sin(x)^3), (x, 0, 1))
Use the examples entering the upper and lower limits of integration.