Integral of e^(x+2) dx
The solution
Detail solution
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There are multiple ways to do this integral.
Method #1
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Let u=x+2.
Then let du=dx and substitute du:
∫eudu
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The integral of the exponential function is itself.
∫eudu=eu
Now substitute u back in:
Method #2
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Rewrite the integrand:
ex+2=e2ex
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The integral of a constant times a function is the constant times the integral of the function:
∫e2exdx=e2∫exdx
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The integral of the exponential function is itself.
∫exdx=ex
So, the result is: e2ex
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Now simplify:
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Add the constant of integration:
ex+2+constant
The answer is:
ex+2+constant
The answer (Indefinite)
[src]
/
|
| x + 2 x + 2
| E dx = C + e
|
/
∫ex+2dx=C+ex+2
The graph
−e2+e3
=
−e2+e3
Use the examples entering the upper and lower limits of integration.