Integral of 3sin4x dx

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 |  3*sin(4*x) dx
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\int\limits_{0}^{1} 3 \sin{\left(4 x \right)}\, dx

Simplify

Detail solution

The integral of a constant times a function is the constant times the integral of the function:

$\int 3 \sin{\left(4 x \right)}\, dx = 3 \int \sin{\left(4 x \right)}\, dx$
1. Let $u = 4 x$ .
  
  Then let $du = 4 dx$ and substitute $\frac{du}{4}$ :
  
  $\int \frac{\sin{\left(u \right)}}{16}\, du$
  1. The integral of a constant times a function is the constant times the integral of the function:
    
    $\int \frac{\sin{\left(u \right)}}{4}\, du = \frac{\int \sin{\left(u \right)}\, du}{4}$
    1. The integral of sine is negative cosine:
      
      $\int \sin{\left(u \right)}\, du = - \cos{\left(u \right)}$
    So, the result is: $- \frac{\cos{\left(u \right)}}{4}$
  Now substitute $u$ back in:
  
  $- \frac{\cos{\left(4 x \right)}}{4}$
So, the result is: $- \frac{3 \cos{\left(4 x \right)}}{4}$
Add the constant of integration:

$- \frac{3 \cos{\left(4 x \right)}}{4}+ \mathrm{constant}$

The answer is:

- \frac{3 \cos{\left(4 x \right)}}{4}+ \mathrm{constant}

The answer (Indefinite) [src]

  /                              
 |                     3*cos(4*x)
 | 3*sin(4*x) dx = C - ----------
 |                         4     
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-{{3\,\cos \left(4\,x\right)}\over{4}}

Simplify

The graph

Plot the graph f(x)

The answer [src]

3   3*cos(4)
- - --------
4      4

3\,\left({{1}\over{4}}-{{\cos 4}\over{4}}\right)

3   3*cos(4)
- - --------
4      4

- \frac{3 \cos{\left(4 \right)}}{4} + \frac{3}{4}

Simplify

Numerical answer [src]

1.24023271564771

1.24023271564771

The graph

Use the examples entering the upper and lower limits of integration.