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x^2-5x=0

x^2-5x=0 equation

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Numerical solution:

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The solution

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x  - 5*x = 0
$$x^{2} - 5 x = 0$$
Detail solution
This equation is of the form
$$a*x^2 + b*x + c = 0$$
A quadratic equation can be solved using the discriminant
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where $D = b^2 - 4 a c$ is the discriminant.
Because
$$a = 1$$
$$b = -5$$
$$c = 0$$
, then
$$D = b^2 - 4 * a * c = $$
$$\left(-1\right) 1 \cdot 4 \cdot 0 + \left(-5\right)^{2} = 25$$
Because D > 0, then the equation has two roots.
$$x_1 = \frac{(-b + \sqrt{D})}{2 a}$$
$$x_2 = \frac{(-b - \sqrt{D})}{2 a}$$
or
$$x_{1} = 5$$
Simplify
$$x_{2} = 0$$
Simplify
Vieta's Theorem
it is reduced quadratic equation
$$p x + x^{2} + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = -5$$
$$q = \frac{c}{a}$$
$$q = 0$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = 5$$
$$x_{1} x_{2} = 0$$
The graph
Rapid solution [src]
x_1 = 0
$$x_{1} = 0$$
x_2 = 5
$$x_{2} = 5$$
Sum and product of roots [src]
sum
0 + 5
$$\left(0\right) + \left(5\right)$$
=
5
$$5$$
product
0 * 5
$$\left(0\right) * \left(5\right)$$
=
0
$$0$$
Numerical answer [src]
x1 = 5.0
x2 = 0.0
x2 = 0.0
The graph
x^2-5x=0 equation