Integral of x^2-5x dx

1. Integrate term-by-term:

   1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

      $$\int x^{2}\, dx = \frac{x^{3}}{3}$$

   1. The integral of a constant times a function is the constant times the integral of the function:

      $$\int \left(- 5 x\right)\, dx = - \int 5 x\, dx$$

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int 5 x\, dx = 5 \int x\, dx$$

         1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int x\, dx = \frac{x^{2}}{2}$$

         So, the result is: $\frac{5 x^{2}}{2}$

      So, the result is: $- \frac{5 x^{2}}{2}$

   The result is: $\frac{x^{3}}{3} - \frac{5 x^{2}}{2}$

2. Now simplify:

   $$\frac{x^{2} \cdot \left(2 x - 15\right)}{6}$$

3. Add the constant of integration:

   $$\frac{x^{2} \cdot \left(2 x - 15\right)}{6}+ \mathrm{constant}$$

The answer is:

$$\frac{x^{2} \cdot \left(2 x - 15\right)}{6}+ \mathrm{constant}$$