Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- -16*x-7*y=-5
- -5*x+5*y=-9
- -2*x+1*y=-8
- 1*x-19*y=-10
- Equation:
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Equation tg(x)=-1
-
Equation sin(x)=3/2
-
Equation 3x-3=7x-3(2x-5)
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Equation k^2+k-2=0
- Limit of the function:
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-5
- -5
- Derivative of:
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-5
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Identical expressions
- - sixteen *x- seven *y=- five
- minus 16 multiply by x minus 7 multiply by y equally minus 5
- minus sixteen multiply by x minus seven multiply by y equally minus five
- -16x-7y=-5
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Similar expressions
- 16*x-7*y=-5
- -16*x-7*y=+5
- -16*x+7*y=-5
Express x in terms of y where -16*x-7*y=-5
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 16 x = 7 y - 5$$
Divide both parts of the equation by -16
We get the answer: x = 5/16 - 7*y/16
-16*x-7*y = -5
Looking for similar summands in the left part:
-16*x - 7*y = -5
Move the summands with the other variables
from left part to right part, we given:
$$- 16 x = 7 y - 5$$
Divide both parts of the equation by -16
x = -5 + 7*y / (-16)
We get the answer: x = 5/16 - 7*y/16
Rapid solution
[src]
5 7*re(y) 7*I*im(y)
x1 = -- - ------- - ---------
16 16 16
$$x_{1} = - \frac{7 \operatorname{re}{\left(y\right)}}{16} - \frac{7 i \operatorname{im}{\left(y\right)}}{16} + \frac{5}{16}$$
x1 = -7*re(y)/16 - 7*i*im(y)/16 + 5/16