Mister Exam

Derivative of sin0.5x

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
sin(0.5*x)
sin(0.5x)\sin{\left(0.5 x \right)}
sin(0.5*x)
Detail solution
  1. Let u=0.5xu = 0.5 x.

  2. The derivative of sine is cosine:

    ddusin(u)=cos(u)\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}

  3. Then, apply the chain rule. Multiply by ddx0.5x\frac{d}{d x} 0.5 x:

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Apply the power rule: xx goes to 11

      So, the result is: 0.50.5

    The result of the chain rule is:

    0.5cos(0.5x)0.5 \cos{\left(0.5 x \right)}


The answer is:

0.5cos(0.5x)0.5 \cos{\left(0.5 x \right)}

The graph
02468-8-6-4-2-10102-2
The first derivative [src]
0.5*cos(0.5*x)
0.5cos(0.5x)0.5 \cos{\left(0.5 x \right)}
The second derivative [src]
-0.25*sin(0.5*x)
0.25sin(0.5x)- 0.25 \sin{\left(0.5 x \right)}
The third derivative [src]
-0.125*cos(0.5*x)
0.125cos(0.5x)- 0.125 \cos{\left(0.5 x \right)}