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Derivative of:
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Derivative of sin(x)/(1+cos(x))
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Limit of the function:
sin(x)/(1+cos(x))
Integral of d{x}:
sin(x)/(1+cos(x))
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sin(x)/(one +cos(x))
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sinus of (x) divide by (one plus co sinus of e of (x))
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Similar expressions
y=(sinx)/(1+cosx)
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y=sinx/1+cosx
sinx/(1+cosx)
sin(x)/(1-cos(x))
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The derivative of the function/ sin(x)/(1+cos(x))

Derivative of sin(x)/(1+cos(x))

The solution

You have entered [src]

  sin(x)  
----------
1 + cos(x)

$$\frac{\sin{\left(x \right)}}{\cos{\left(x \right)} + 1}$$

sin(x)/(1 + cos(x))

Detail solution

Apply the quotient rule, which is:

$\frac{d}{d x} \frac{f{\left(x \right)}}{g{\left(x \right)}} = \frac{- f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}}{g^{2}{\left(x \right)}}$

$f{\left(x \right)} = \sin{\left(x \right)}$ and $g{\left(x \right)} = \cos{\left(x \right)} + 1$ .

To find $\frac{d}{d x} f{\left(x \right)}$ :
1. The derivative of sine is cosine:
  
  $\frac{d}{d x} \sin{\left(x \right)} = \cos{\left(x \right)}$
To find $\frac{d}{d x} g{\left(x \right)}$ :
1. Differentiate $\cos{\left(x \right)} + 1$ term by term:
  1. The derivative of the constant $1$ is zero.
  2. The derivative of cosine is negative sine:
    
    $\frac{d}{d x} \cos{\left(x \right)} = - \sin{\left(x \right)}$
  The result is: $- \sin{\left(x \right)}$
Now plug in to the quotient rule:

$\frac{\left(\cos{\left(x \right)} + 1\right) \cos{\left(x \right)} + \sin^{2}{\left(x \right)}}{\left(\cos{\left(x \right)} + 1\right)^{2}}$
Now simplify:

$\frac{1}{\cos{\left(x \right)} + 1}$

The answer is:

$\frac{1}{\cos{\left(x \right)} + 1}$

The graph

Plot the graph f(x)

Plot the graph f'(x)

The first derivative [src]

                   2      
  cos(x)        sin (x)   
---------- + -------------
1 + cos(x)               2
             (1 + cos(x))

$$\frac{\cos{\left(x \right)}}{\cos{\left(x \right)} + 1} + \frac{\sin^{2}{\left(x \right)}}{\left(\cos{\left(x \right)} + 1\right)^{2}}$$

Simplify

The second derivative [src]

/          2                          \       
|     2*sin (x)                       |       
|     ---------- + cos(x)             |       
|     1 + cos(x)             2*cos(x) |       
|-1 + ------------------- + ----------|*sin(x)
\          1 + cos(x)       1 + cos(x)/       
----------------------------------------------
                  1 + cos(x)

$$\frac{\left(-1 + \frac{\cos{\left(x \right)} + \frac{2 \sin^{2}{\left(x \right)}}{\cos{\left(x \right)} + 1}}{\cos{\left(x \right)} + 1} + \frac{2 \cos{\left(x \right)}}{\cos{\left(x \right)} + 1}\right) \sin{\left(x \right)}}{\cos{\left(x \right)} + 1}$$

Simplify

The third derivative [src]

                               /                         2     \                                 
                          2    |      6*cos(x)      6*sin (x)  |     /     2             \       
                       sin (x)*|-1 + ---------- + -------------|     |2*sin (x)          |       
               2               |     1 + cos(x)               2|   3*|---------- + cos(x)|*cos(x)
          3*sin (x)            \                  (1 + cos(x)) /     \1 + cos(x)         /       
-cos(x) - ---------- + ----------------------------------------- + ------------------------------
          1 + cos(x)                   1 + cos(x)                            1 + cos(x)          
-------------------------------------------------------------------------------------------------
                                            1 + cos(x)

$$\frac{- \cos{\left(x \right)} + \frac{3 \left(\cos{\left(x \right)} + \frac{2 \sin^{2}{\left(x \right)}}{\cos{\left(x \right)} + 1}\right) \cos{\left(x \right)}}{\cos{\left(x \right)} + 1} + \frac{\left(-1 + \frac{6 \cos{\left(x \right)}}{\cos{\left(x \right)} + 1} + \frac{6 \sin^{2}{\left(x \right)}}{\left(\cos{\left(x \right)} + 1\right)^{2}}\right) \sin^{2}{\left(x \right)}}{\cos{\left(x \right)} + 1} - \frac{3 \sin^{2}{\left(x \right)}}{\cos{\left(x \right)} + 1}}{\cos{\left(x \right)} + 1}$$

Simplify

The graph

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Derivative of sin(x)/(1+cos(x))

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The solution