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Sum of series x*a^x



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The solution

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x = 1     
x=1axx\sum_{x=1}^{\infty} a^{x} x
Sum(x*a^x, (x, 1, oo))
The radius of convergence of the power series
Given number:
axxa^{x} x
It is a series of species
ax(cxx0)dxa_{x} \left(c x - x_{0}\right)^{d x}
- power series.
The radius of convergence of a power series can be calculated by the formula:
Rd=x0+limxaxax+1cR^{d} = \frac{x_{0} + \lim_{x \to \infty} \left|{\frac{a_{x}}{a_{x + 1}}}\right|}{c}
In this case
ax=xa_{x} = x
and
x0=ax_{0} = - a
,
d=1d = 1
,
c=0c = 0
then
R=~(a+limx(xx+1))R = \tilde{\infty} \left(- a + \lim_{x \to \infty}\left(\frac{x}{x + 1}\right)\right)
Let's take the limit
we find
R=~(1a)R = \tilde{\infty} \left(1 - a\right)
The answer [src]
/    a                  
| --------   for |a| < 1
|        2              
| (1 - a)               
|                       
|  oo                   
< ___                   
| \  `                  
|  \      x             
|  /   x*a    otherwise 
| /__,                  
|x = 1                  
\                       
{a(1a)2fora<1x=1axxotherwise\begin{cases} \frac{a}{\left(1 - a\right)^{2}} & \text{for}\: \left|{a}\right| < 1 \\\sum_{x=1}^{\infty} a^{x} x & \text{otherwise} \end{cases}
Piecewise((a/(1 - a)^2, |a| < 1), (Sum(x*a^x, (x, 1, oo)), True))

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