Mister Exam
Other calculators
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How to use it?
- Factor squared:
- x^2+x+3
- -y^4-y^2+4
- -y^4-y^2-3
- 2*x^2+x*y-y^2
- Factor polynomial:
- x^2+3
- x^3+6*x^2-x-6
- x^3-x
- x^4+x^2+1
- Least common denominator:
- (-cos(x)^5)/5+2*cos(x)^3/3-cos(x)
- (5/s)*(2/((1/5)*s+1))*(1/(s+1))
- (u^2-4*u+16)/(16*u^2-1)*(4*u^2+u)/(u^3+64)
- 1/(3*sqrt(1-x^2/9))
- How do you in partial fractions?:
- (2x+3)/(x^2-9)
- (pi*a^2+pi/4)/(pi*a^2+pi/2)
- (2x-1)/(x*(x+2)^2*(x-4))
- x/(x^2+1)
- Graphing y =:
- x^2+x+3
- Integral of d{x}:
-
x^2+x+3
- Canonical form:
- x^2+x+3
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Identical expressions
- x^ two +x+ three
- x squared plus x plus 3
- x to the power of two plus x plus three
- x2+x+3
- x²+x+3
- x to the power of 2+x+3
-
Similar expressions
- x^2+x-3
- x^2-x+3
Factor x^2+x+3 squared
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} + x\right) + 3$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = 3$$
Then
$$m = \frac{1}{2}$$
$$n = \frac{11}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} + \frac{11}{4}$$
$$\left(x^{2} + x\right) + 3$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = 3$$
Then
$$m = \frac{1}{2}$$
$$n = \frac{11}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} + \frac{11}{4}$$
Factorization
[src]
/ ____\ / ____\ | 1 I*\/ 11 | | 1 I*\/ 11 | |x + - + --------|*|x + - - --------| \ 2 2 / \ 2 2 /
$$\left(x + \left(\frac{1}{2} - \frac{\sqrt{11} i}{2}\right)\right) \left(x + \left(\frac{1}{2} + \frac{\sqrt{11} i}{2}\right)\right)$$
(x + 1/2 + i*sqrt(11)/2)*(x + 1/2 - i*sqrt(11)/2)