Mister Exam
Other calculators
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How to use it?
- Factor squared:
- y^4-y^2+15
- y^4-y^2-3
- y^4-12*y^2+7
- -y^2+4*y+3
- Factor polynomial:
- x^2-4
- x-x^2
- x^8+1
- x^6-8
- Least common denominator:
- (2*a+b)/(a^2-b^2)+1/(a+b)
- (234/(((7/20)*p+1)*(p+1)*((111/10)*p+1)))*((3/10)+10/p)
- (z/x-z+x+z/z)/x/x^2-z^2
- (z/x-z+x+z/z)/x/x^2-x*z^2
- How do you in partial fractions?:
- 2*(-1+(-1+x)/(2+x))/(2+x)^2
- (1+(1+(1+x)/(1-3x))/(1-3\(1+x)/(1-3x)))/(-3\(1+(1+x)/(1-3x))/(1-3\(1+x)/(1-3x)))
- y/(y+2)+(1/(4-y^2)-1/(4-4*y+y^2))/(2/(y-2)^2)
- (c^4-3*c^2+2)/(c^5+1)
- Derivative of:
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x^2-x+3
- Graphing y =:
- x^2-x+3
- Factor polynomial:
- x^2-x+3
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Identical expressions
- x^ two -x+ three
- x squared minus x plus 3
- x to the power of two minus x plus three
- x2-x+3
- x²-x+3
- x to the power of 2-x+3
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Similar expressions
- x^2+x+3
- x^2-x-3
Factor x^2-x+3 squared
The solution
Factorization
[src]
/ ____\ / ____\ | 1 I*\/ 11 | | 1 I*\/ 11 | |x + - - + --------|*|x + - - - --------| \ 2 2 / \ 2 2 /
$$\left(x + \left(- \frac{1}{2} - \frac{\sqrt{11} i}{2}\right)\right) \left(x + \left(- \frac{1}{2} + \frac{\sqrt{11} i}{2}\right)\right)$$
(x - 1/2 + i*sqrt(11)/2)*(x - 1/2 - i*sqrt(11)/2)
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} - x\right) + 3$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -1$$
$$c = 3$$
Then
$$m = - \frac{1}{2}$$
$$n = \frac{11}{4}$$
So,
$$\left(x - \frac{1}{2}\right)^{2} + \frac{11}{4}$$
$$\left(x^{2} - x\right) + 3$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -1$$
$$c = 3$$
Then
$$m = - \frac{1}{2}$$
$$n = \frac{11}{4}$$
So,
$$\left(x - \frac{1}{2}\right)^{2} + \frac{11}{4}$$