Mister Exam
Other calculators
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How to use it?
- Factor squared:
- y^4-9*y^2-3
- y^4-y^2-9
- x^2+x-3
- y^4-9*y^2+8
- Factor polynomial:
- m^5-m^3
- p^9+64
- m^6+m^3
- x^2-9
- Least common denominator:
- (z+z/q)*(z-z/q)
- (z-x)/r/m/(r*r)
- (z-x)/(r/(m/(r^2)))
- (z-t)/(z+t)/(z-t)^2
- How do you in partial fractions?:
- (5x^2+9x-2)/(x^2-5x-14)
- (x^2-1)/(x^2+1)
- 4*(1-2/(-1+2*2)+2/(-1+2*2)^2)*exp(-2+2*2)/(-1+2*2)
- (x^2-1)/(x^3+1)
- Graphing y =:
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x^2+x-3
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Identical expressions
- x^ two +x- three
- x squared plus x minus 3
- x to the power of two plus x minus three
- x2+x-3
- x²+x-3
- x to the power of 2+x-3
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Similar expressions
- x^2+x+3
- x^2-x-3
Factor x^2+x-3 squared
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} + x\right) - 3$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = -3$$
Then
$$m = \frac{1}{2}$$
$$n = - \frac{13}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} - \frac{13}{4}$$
$$\left(x^{2} + x\right) - 3$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = -3$$
Then
$$m = \frac{1}{2}$$
$$n = - \frac{13}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} - \frac{13}{4}$$
Factorization
[src]
/ ____\ / ____\ | 1 \/ 13 | | 1 \/ 13 | |x + - - ------|*|x + - + ------| \ 2 2 / \ 2 2 /
$$\left(x + \left(\frac{1}{2} - \frac{\sqrt{13}}{2}\right)\right) \left(x + \left(\frac{1}{2} + \frac{\sqrt{13}}{2}\right)\right)$$
(x + 1/2 - sqrt(13)/2)*(x + 1/2 + sqrt(13)/2)