Mister Exam
Other calculators
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How to use it?
- Factor squared:
- -y^4+y^2-4
- y^4+y^2+2
- y^4+y^2+4
- y^2+4*y-3
- Factor polynomial:
- x*y^3-x^3*y^2
- x^3+7*x^2+15*x+9
- x^2+x-6
- x^2+4
- Least common denominator:
- (a/5+a/7)*a^2/4
- (a+1/a+2)/a+1
- 4*x^(3/2)/3+2*sqrt(x)+x^5/5+e^(5*x^3+1)/15
- 2/(a+2)+(a-2)/(a^2+4*a+4)/(a/(2*a-4)+(a^2+4)/(8-2*a)-2/(2*a+a^2))
- How do you in partial fractions?:
- (z-(5*z)/z+1)/(z-4)/(z+1)
- ((z)-((7*z)/(z+3)))*((z+3)/(z-4))
- (z/c+c/z)/((z^2+c^2)/(5*z^9*c))
- 1/(2*sqrt(x))
- Graphing y =:
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x^2+x-3
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Identical expressions
- x^ two +x- three
- x squared plus x minus 3
- x to the power of two plus x minus three
- x2+x-3
- x²+x-3
- x to the power of 2+x-3
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Similar expressions
- x^2+x+3
- x^2-x-3
Factor x^2+x-3 squared
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} + x\right) - 3$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = -3$$
Then
$$m = \frac{1}{2}$$
$$n = - \frac{13}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} - \frac{13}{4}$$
$$\left(x^{2} + x\right) - 3$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = -3$$
Then
$$m = \frac{1}{2}$$
$$n = - \frac{13}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} - \frac{13}{4}$$
Factorization
[src]
/ ____\ / ____\ | 1 \/ 13 | | 1 \/ 13 | |x + - - ------|*|x + - + ------| \ 2 2 / \ 2 2 /
$$\left(x + \left(\frac{1}{2} - \frac{\sqrt{13}}{2}\right)\right) \left(x + \left(\frac{1}{2} + \frac{\sqrt{13}}{2}\right)\right)$$
(x + 1/2 - sqrt(13)/2)*(x + 1/2 + sqrt(13)/2)