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How do you in partial fractions?:
(2x-1)/(x*(x+2)^2*(x-4))
(z*z-1/2*z)/(z*z-z+1)*z/(z-1/2)
(m^2-1)/(m+1)
1/(2*x^2)
Factor polynomial:
x^3+y^3
x^3-x^2-x^3+2
x^2*y+14*x*y^2+49*y^3
c^3+d^3
Least common denominator:
x^4/4+5*x^2/2-4*x
((x+1)^2*(8*x-4))^(1/3)*(8*(x+1)^2/3+(2+2*x)*(8*x-4)/3)/((x+1)^2*(8*x-4))
(pi*a^2+pi/4)/(pi*a^2+pi/2)
(-cos(x)^5)/5+2*cos(x)^3/3-cos(x)
Factor squared:
-y^4-y^2-3
y^4+y^2+6
x^2-x-6
x^2+3*x+4
Identical expressions
(two x- one)/(x*(x+ two)^2*(x- four))
(2x minus 1) divide by (x multiply by (x plus 2) squared multiply by (x minus 4))
(two x minus one) divide by (x multiply by (x plus two) squared multiply by (x minus four))
(2x-1)/(x*(x+2)2*(x-4))
2x-1/x*x+22*x-4
(2x-1)/(x*(x+2)²*(x-4))
(2x-1)/(x*(x+2) to the power of 2*(x-4))
(2x-1)/(x(x+2)^2(x-4))
(2x-1)/(x(x+2)2(x-4))
2x-1/xx+22x-4
2x-1/xx+2^2x-4
(2x-1) divide by (x*(x+2)^2*(x-4))
Similar expressions
(2x-1)/(x*(x+2)^2*(x+4))
(2x+1)/(x*(x+2)^2*(x-4))
(2x-1)/(x*(x-2)^2*(x-4))

Expression simplification/ Fraction Decomposition into the simple/ (2x-1)/(x*(x+2)^2*(x-4))

How do you (2x-1)/(x(x+2)^2(x-4)) in partial fractions?

The solution

You have entered [src]

     2*x - 1      
------------------
         2        
x*(x + 2) *(x - 4)

$$\frac{2 x - 1}{x \left(x + 2\right)^{2} \left(x - 4\right)}$$

(2*x - 1)/(((x*(x + 2)^2)*(x - 4)))

Fraction decomposition [src]

-5/(12*(2 + x)^2) - 1/(9*(2 + x)) + 1/(16*x) + 7/(144*(-4 + x))

$$- \frac{1}{9 \left(x + 2\right)} - \frac{5}{12 \left(x + 2\right)^{2}} + \frac{7}{144 \left(x - 4\right)} + \frac{1}{16 x}$$

       5            1        1          7      
- ----------- - --------- + ---- + ------------
            2   9*(2 + x)   16*x   144*(-4 + x)
  12*(2 + x)

General simplification [src]

      -1 + 2*x     
-------------------
                  2
x*(-4 + x)*(2 + x)

$$\frac{2 x - 1}{x \left(x - 4\right) \left(x + 2\right)^{2}}$$

(-1 + 2*x)/(x*(-4 + x)*(2 + x)^2)

Rational denominator [src]

      -1 + 2*x     
-------------------
                  2
x*(-4 + x)*(2 + x)

$$\frac{2 x - 1}{x \left(x - 4\right) \left(x + 2\right)^{2}}$$

(-1 + 2*x)/(x*(-4 + x)*(2 + x)^2)

Common denominator [src]

     -1 + 2*x    
-----------------
 4              2
x  - 16*x - 12*x

$$\frac{2 x - 1}{x^{4} - 12 x^{2} - 16 x}$$

(-1 + 2*x)/(x^4 - 16*x - 12*x^2)

Trigonometric part [src]

      -1 + 2*x     
-------------------
                  2
x*(-4 + x)*(2 + x)

$$\frac{2 x - 1}{x \left(x - 4\right) \left(x + 2\right)^{2}}$$

(-1 + 2*x)/(x*(-4 + x)*(2 + x)^2)

Combinatorics [src]

      -1 + 2*x     
-------------------
                  2
x*(-4 + x)*(2 + x)

$$\frac{2 x - 1}{x \left(x - 4\right) \left(x + 2\right)^{2}}$$

(-1 + 2*x)/(x*(-4 + x)*(2 + x)^2)

Powers [src]

      -1 + 2*x     
-------------------
                  2
x*(-4 + x)*(2 + x)

$$\frac{2 x - 1}{x \left(x - 4\right) \left(x + 2\right)^{2}}$$

(-1 + 2*x)/(x*(-4 + x)*(2 + x)^2)

Assemble expression [src]

      -1 + 2*x     
-------------------
                  2
x*(-4 + x)*(2 + x)

$$\frac{2 x - 1}{x \left(x - 4\right) \left(x + 2\right)^{2}}$$

(-1 + 2*x)/(x*(-4 + x)*(2 + x)^2)

Combining rational expressions [src]

      -1 + 2*x     
-------------------
                  2
x*(-4 + x)*(2 + x)

$$\frac{2 x - 1}{x \left(x - 4\right) \left(x + 2\right)^{2}}$$

(-1 + 2*x)/(x*(-4 + x)*(2 + x)^2)

Numerical answer [src]

0.25*(-1.0 + 2.0*x)/(x*(1 + 0.5*x)^2*(-4.0 + x))

0.25*(-1.0 + 2.0*x)/(x*(1 + 0.5*x)^2*(-4.0 + x))

Expand expression [src]

     2*x - 1      
------------------
                 2
x*(x - 4)*(x + 2)

$$\frac{2 x - 1}{x \left(x - 4\right) \left(x + 2\right)^{2}}$$

(2*x - 1)/(x*(x - 4)*(x + 2)^2)

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Identical expressions

Similar expressions

How do you (2x-1)/(x*(x+2)^2*(x-4)) in partial fractions?

The solution

How do you (2x-1)/(x(x+2)^2(x-4)) in partial fractions?