Mister Exam
Other calculators
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How to use it?
- Factor squared:
- y^4+y^2+1
- y^4-9*y^2-3
- x^2-x-4
- x^2+x+1
- Factor polynomial:
- x^10-1
- m^6+m^3
- x^2-x^2
- m^5-m^3
- Least common denominator:
- (z-t)/(z+t)/(z-t)^2
- (z*sqrt(z^2-a^2))/2-(a^2*log(2*sqrt(z^2-a^2)+2*z))/2
- (z-(5*z)/z+1)/(z-4)/(z+1)
- ((z^2-z)/(z^2-9))^-1/(z^2-3*z)/(z-1)
- How do you in partial fractions?:
- 2/(a+2)+(a-2)/(a^2+4*a+4)/(a/(2*a-4)+(a^2+4)/(8-2*a)-2/(2*a+a^2))
- sqrt((w^2*(-t^2)/(1+t^2*w^2))^2+(t*w/(1+t^2*w^2))^2)
- ((z+2)/(2*z+4))+((2*z+1)/(3*z-4))
- (x+5)/(x^2+22*x+85)
- Derivative of:
-
x^2+x+1
- Graphing y =:
- x^2+x+1
- Factor polynomial:
- x^2+x+1
-
Identical expressions
- x^ two +x+ one
- x squared plus x plus 1
- x to the power of two plus x plus one
- x2+x+1
- x²+x+1
- x to the power of 2+x+1
-
Similar expressions
- x^2-x+1
- x^2+x-1
Factor x^2+x+1 squared
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} + x\right) + 1$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = 1$$
Then
$$m = \frac{1}{2}$$
$$n = \frac{3}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} + \frac{3}{4}$$
$$\left(x^{2} + x\right) + 1$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = 1$$
Then
$$m = \frac{1}{2}$$
$$n = \frac{3}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} + \frac{3}{4}$$
Factorization
[src]
/ ___\ / ___\ | 1 I*\/ 3 | | 1 I*\/ 3 | |x + - + -------|*|x + - - -------| \ 2 2 / \ 2 2 /
$$\left(x + \left(\frac{1}{2} - \frac{\sqrt{3} i}{2}\right)\right) \left(x + \left(\frac{1}{2} + \frac{\sqrt{3} i}{2}\right)\right)$$
(x + 1/2 + i*sqrt(3)/2)*(x + 1/2 - i*sqrt(3)/2)