General simplification
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$$- y^{4} + 8 y^{2} - 13$$
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(- y^{4} + 8 y^{2}\right) - 13$$
To do this, let's use the formula
$$a y^{4} + b y^{2} + c = a \left(m + y^{2}\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = -1$$
$$b = 8$$
$$c = -13$$
Then
$$m = -4$$
$$n = 3$$
So,
$$3 - \left(y^{2} - 4\right)^{2}$$
/ ___________\ / ___________\ / ___________\ / ___________\
| / ___ | | / ___ | | / ___ | | / ___ |
\x + \/ 4 - \/ 3 /*\x - \/ 4 - \/ 3 /*\x + \/ 4 + \/ 3 /*\x - \/ 4 + \/ 3 /
$$\left(x - \sqrt{4 - \sqrt{3}}\right) \left(x + \sqrt{4 - \sqrt{3}}\right) \left(x + \sqrt{\sqrt{3} + 4}\right) \left(x - \sqrt{\sqrt{3} + 4}\right)$$
(((x + sqrt(4 - sqrt(3)))*(x - sqrt(4 - sqrt(3))))*(x + sqrt(4 + sqrt(3))))*(x - sqrt(4 + sqrt(3)))
Assemble expression
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$$- y^{4} + 8 y^{2} - 13$$
Combining rational expressions
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$$y^{2} \left(8 - y^{2}\right) - 13$$
$$- y^{4} + 8 y^{2} - 13$$
Rational denominator
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$$- y^{4} + 8 y^{2} - 13$$
$$- y^{4} + 8 y^{2} - 13$$
$$- y^{4} + 8 y^{2} - 13$$
$$- y^{4} + 8 y^{2} - 13$$