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Factor polynomial x^2-4*x-5

An expression to simplify:

The solution

You have entered [src]
 2          
x  - 4*x - 5
$$\left(x^{2} - 4 x\right) - 5$$
x^2 - 4*x - 5
Factorization [src]
(x + 1)*(x - 5)
$$\left(x - 5\right) \left(x + 1\right)$$
(x + 1)*(x - 5)
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} - 4 x\right) - 5$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -4$$
$$c = -5$$
Then
$$m = -2$$
$$n = -9$$
So,
$$\left(x - 2\right)^{2} - 9$$
General simplification [src]
      2      
-5 + x  - 4*x
$$x^{2} - 4 x - 5$$
-5 + x^2 - 4*x
Trigonometric part [src]
      2      
-5 + x  - 4*x
$$x^{2} - 4 x - 5$$
-5 + x^2 - 4*x
Common denominator [src]
      2      
-5 + x  - 4*x
$$x^{2} - 4 x - 5$$
-5 + x^2 - 4*x
Powers [src]
      2      
-5 + x  - 4*x
$$x^{2} - 4 x - 5$$
-5 + x^2 - 4*x
Combining rational expressions [src]
-5 + x*(-4 + x)
$$x \left(x - 4\right) - 5$$
-5 + x*(-4 + x)
Rational denominator [src]
      2      
-5 + x  - 4*x
$$x^{2} - 4 x - 5$$
-5 + x^2 - 4*x
Assemble expression [src]
      2      
-5 + x  - 4*x
$$x^{2} - 4 x - 5$$
-5 + x^2 - 4*x
Numerical answer [src]
-5.0 + x^2 - 4.0*x
-5.0 + x^2 - 4.0*x
Combinatorics [src]
(1 + x)*(-5 + x)
$$\left(x - 5\right) \left(x + 1\right)$$
(1 + x)*(-5 + x)