Mister Exam
Other calculators
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How to use it?
- Factor squared:
- x^2+4*x+5
- x^2+x-4
- p^4+9*p^2+5
- y^4-y^2+9
- Factor polynomial:
- x^2-49
- -y^2+y
- x^4+81
- x^4-x^2
- Least common denominator:
- (z*(z^2+6*z+1)-(4*z*(z+1)))/(z-1)^3+z*(z-1)/(z+1)^3
- (z^5-5*z^3+10*z-10/z+1/5*z^3-1/z^5)*(z^3-3*z+3/z-1/z^3)
- ((y-9)/(y-8))*((y^2-64)/(y^2-16*y+64))
- sin((x-y)/2)-sin((x+y)/2)
- How do you in partial fractions?:
- -1/(2*x^2)
- (pi*a^2+pi/4)/(pi*a^2+pi/2)
- 2432902008176640000/(-2+x)^21
- -x^2/(x-2)^2+2*x/(x-2)
- Canonical form:
- x^2+4*x+5
- Graphing y =:
-
x^2+4*x+5
- Integral of d{x}:
- x^2+4*x+5
-
Identical expressions
- x^ two + four *x+ five
- x squared plus 4 multiply by x plus 5
- x to the power of two plus four multiply by x plus five
- x2+4*x+5
- x²+4*x+5
- x to the power of 2+4*x+5
- x^2+4x+5
- x2+4x+5
-
Similar expressions
- x^2-4*x+5
- x^2+4*x-5
Factor x^2+4*x+5 squared
The solution
Factorization
[src]
(x + 2 + I)*(x + 2 - I)
$$\left(x + \left(2 - i\right)\right) \left(x + \left(2 + i\right)\right)$$
(x + 2 + i)*(x + 2 - i)
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} + 4 x\right) + 5$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 4$$
$$c = 5$$
Then
$$m = 2$$
$$n = 1$$
So,
$$\left(x + 2\right)^{2} + 1$$
$$\left(x^{2} + 4 x\right) + 5$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 4$$
$$c = 5$$
Then
$$m = 2$$
$$n = 1$$
So,
$$\left(x + 2\right)^{2} + 1$$