Mister Exam
Other calculators
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How to use it?
- Factor squared:
- y^4+y^2+2
- y^4+y^2-15
- y^4-y^2-5
- -y^4+8*y^2-8
- Factor polynomial:
- x^2+3
- x^4-x
- x*y^3-x^3*y^2
- x^2-1
- Least common denominator:
- 4*x^(3/2)/3+2*sqrt(x)+x^5/5+e^(5*x^3+1)/15
- z*((-z)*log(x)/c+z*log(y)/c)
- (z*z-1/2*z)/(z*z-z+1)*z/(z-1/2)
- -x^2/(x-2)^2+2*x/(x-2)
- How do you in partial fractions?:
- (z^2-4*z+16)/(16*z^2-1)*(4*z^2+z)/(z^3+64)-(z+4)/(4*z^2-z)
- (5x^2+9x-2)/(x^2-5x-14)
- y/(y+2)+(1/(4-y^2)-1/(4-4*y+y^2))/(2/(y-2)^2)
- 1/(2*sqrt(x))
- Graphing y =:
- x^2+4*x-5
- Integral of d{x}:
-
x^2+4*x-5
- Factor polynomial:
- x^2+4*x-5
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Identical expressions
- x^ two + four *x- five
- x squared plus 4 multiply by x minus 5
- x to the power of two plus four multiply by x minus five
- x2+4*x-5
- x²+4*x-5
- x to the power of 2+4*x-5
- x^2+4x-5
- x2+4x-5
-
Similar expressions
- x^2-4*x-5
- x^2+4*x+5
Factor x^2+4*x-5 squared
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} + 4 x\right) - 5$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 4$$
$$c = -5$$
Then
$$m = 2$$
$$n = -9$$
So,
$$\left(x + 2\right)^{2} - 9$$
$$\left(x^{2} + 4 x\right) - 5$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 4$$
$$c = -5$$
Then
$$m = 2$$
$$n = -9$$
So,
$$\left(x + 2\right)^{2} - 9$$