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How to use it?
How do you in partial fractions?
:
-1/(2*x^2)
1/(x-1)^2
((y-9)/(y-8))*((y^2-64)/(y^2-16*y+64))
((9*b)/(a-b))*((a^2-a*b)/(45*b))
Factor polynomial
:
x^4+1
y^2-16
x^4-1
z^2-8*p^z-z+4*p+16*p^2
Least common denominator
:
((3*c+1)/(c-1)+c)/(c+1)
y/(b*y-2*b^2)-2/(y^2+y-2*b*y-2*b)*(1+(3*y+y^2)/(3+y))
((x*x^(1/2)-x)^3)/((((x^(3/4)-1)/(x^(1/4)-1)-x^(1/2))*(1-x))^3)
(z/(z+6)*(z+6))-(z/(z-6)*(z+6))
Factor squared
:
-y^2+4*y-3
-y^2-4*y-3
3*x^2+5*x-3
y^2+4*y-3
Limit of the function
:
-1/(2*x^2)
Identical expressions
- one /(two *x^ two)
minus 1 divide by (2 multiply by x squared )
minus one divide by (two multiply by x to the power of two)
-1/(2*x2)
-1/2*x2
-1/(2*x²)
-1/(2*x to the power of 2)
-1/(2x^2)
-1/(2x2)
-1/2x2
-1/2x^2
-1 divide by (2*x^2)
Similar expressions
1/(2*x^2)
Expression simplification
/
Fraction Decomposition into the simple
/
-1/(2*x^2)
How do you -1/(2*x^2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
-1 ---- 2 2*x
$$- \frac{1}{2 x^{2}}$$
-1/(2*x^2)
Fraction decomposition
[src]
-1/(2*x^2)
$$- \frac{1}{2 x^{2}}$$
-1 ---- 2 2*x
Numerical answer
[src]
-0.5/x^2
-0.5/x^2