General simplification
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$$2 x^{2} + x y - y^{2}$$
The perfect square
Let's highlight the perfect square of the square three-member
$$- y^{2} + \left(2 x^{2} + x y\right)$$
Let us write down the identical expression
$$- y^{2} + \left(2 x^{2} + x y\right) = - \frac{9 y^{2}}{8} + \left(2 x^{2} + x y + \frac{y^{2}}{8}\right)$$
or
$$- y^{2} + \left(2 x^{2} + x y\right) = - \frac{9 y^{2}}{8} + \left(\sqrt{2} x + \frac{\sqrt{2} y}{4}\right)^{2}$$
in the view of the product
$$\left(- \sqrt{\frac{9}{8}} y + \left(\sqrt{2} x + \frac{\sqrt{2}}{4} y\right)\right) \left(\sqrt{\frac{9}{8}} y + \left(\sqrt{2} x + \frac{\sqrt{2}}{4} y\right)\right)$$
$$\left(- \frac{3 \sqrt{2}}{4} y + \left(\sqrt{2} x + \frac{\sqrt{2}}{4} y\right)\right) \left(\frac{3 \sqrt{2}}{4} y + \left(\sqrt{2} x + \frac{\sqrt{2}}{4} y\right)\right)$$
$$\left(\sqrt{2} x + y \left(- \frac{3 \sqrt{2}}{4} + \frac{\sqrt{2}}{4}\right)\right) \left(\sqrt{2} x + y \left(\frac{\sqrt{2}}{4} + \frac{3 \sqrt{2}}{4}\right)\right)$$
$$\left(\sqrt{2} x - \frac{\sqrt{2} y}{2}\right) \left(\sqrt{2} x + \sqrt{2} y\right)$$
/ y\
(x + y)*|x - -|
\ 2/
$$\left(x - \frac{y}{2}\right) \left(x + y\right)$$
Assemble expression
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$$2 x^{2} + x y - y^{2}$$
Rational denominator
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$$2 x^{2} + x y - y^{2}$$
$$\left(x + y\right) \left(2 x - y\right)$$
$$2 x^{2} + x y - y^{2}$$
Combining rational expressions
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$$x \left(2 x + y\right) - y^{2}$$
$$2 x^{2} + x y - y^{2}$$
$$2 x^{2} + x y - y^{2}$$