The perfect square
Let's highlight the perfect square of the square three-member
$$14 b^{2} + \left(- b 4 y - y^{2}\right)$$
Let us write down the identical expression
$$14 b^{2} + \left(- b 4 y - y^{2}\right) = - \frac{9 y^{2}}{7} + \left(14 b^{2} - 4 b y + \frac{2 y^{2}}{7}\right)$$
or
$$14 b^{2} + \left(- b 4 y - y^{2}\right) = - \frac{9 y^{2}}{7} + \left(\sqrt{14} b - \frac{\sqrt{14} y}{7}\right)^{2}$$
in the view of the product
$$\left(- \sqrt{\frac{9}{7}} y + \left(\sqrt{14} b + - \frac{\sqrt{14}}{7} y\right)\right) \left(\sqrt{\frac{9}{7}} y + \left(\sqrt{14} b + - \frac{\sqrt{14}}{7} y\right)\right)$$
$$\left(- \frac{3 \sqrt{7}}{7} y + \left(\sqrt{14} b + - \frac{\sqrt{14}}{7} y\right)\right) \left(\frac{3 \sqrt{7}}{7} y + \left(\sqrt{14} b + - \frac{\sqrt{14}}{7} y\right)\right)$$
$$\left(\sqrt{14} b + y \left(- \frac{\sqrt{14}}{7} + \frac{3 \sqrt{7}}{7}\right)\right) \left(\sqrt{14} b + y \left(- \frac{3 \sqrt{7}}{7} - \frac{\sqrt{14}}{7}\right)\right)$$
$$\left(\sqrt{14} b + y \left(- \frac{\sqrt{14}}{7} + \frac{3 \sqrt{7}}{7}\right)\right) \left(\sqrt{14} b + y \left(- \frac{3 \sqrt{7}}{7} - \frac{\sqrt{14}}{7}\right)\right)$$
/ / ___\\ / / ___\\
| y*\2 - 3*\/ 2 /| | y*\2 + 3*\/ 2 /|
|b - ---------------|*|b - ---------------|
\ 14 / \ 14 /
$$\left(b - \frac{y \left(2 - 3 \sqrt{2}\right)}{14}\right) \left(b - \frac{y \left(2 + 3 \sqrt{2}\right)}{14}\right)$$
(b - y*(2 - 3*sqrt(2))/14)*(b - y*(2 + 3*sqrt(2))/14)
General simplification
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$$14 b^{2} - 4 b y - y^{2}$$
$$14 b^{2} - 4 b y - y^{2}$$
$$14 b^{2} - 4 b y - y^{2}$$
-y^2 + 14.0*b^2 - 4.0*b*y
-y^2 + 14.0*b^2 - 4.0*b*y
Combining rational expressions
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$$14 b^{2} + y \left(- 4 b - y\right)$$
$$14 b^{2} - 4 b y - y^{2}$$
Assemble expression
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$$14 b^{2} - 4 b y - y^{2}$$
Rational denominator
[src]
$$14 b^{2} - 4 b y - y^{2}$$
$$14 b^{2} - 4 b y - y^{2}$$