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How do you (x^3-4)/(x-2)^2 in partial fractions?

An expression to simplify:

The solution

You have entered [src]
  3     
 x  - 4 
--------
       2
(x - 2) 
$$\frac{x^{3} - 4}{\left(x - 2\right)^{2}}$$
(x^3 - 4)/(x - 2)^2
Fraction decomposition [src]
4 + x + 4/(-2 + x)^2 + 12/(-2 + x)
$$x + 4 + \frac{12}{x - 2} + \frac{4}{\left(x - 2\right)^{2}}$$
            4         12  
4 + x + --------- + ------
                2   -2 + x
        (-2 + x)          
Numerical answer [src]
0.25*(-4.0 + x^3)/(-1 + 0.5*x)^2
0.25*(-4.0 + x^3)/(-1 + 0.5*x)^2
Common denominator [src]
         -20 + 12*x 
4 + x + ------------
             2      
        4 + x  - 4*x
$$x + \frac{12 x - 20}{x^{2} - 4 x + 4} + 4$$
4 + x + (-20 + 12*x)/(4 + x^2 - 4*x)