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How do you (x+1)/(x^3-1) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
x + 1 
------
 3    
x  - 1
$$\frac{x + 1}{x^{3} - 1}$$
(x + 1)/(x^3 - 1)
Fraction decomposition [src]
2/(3*(-1 + x)) - (1 + 2*x)/(3*(1 + x + x^2))
$$- \frac{2 x + 1}{3 \left(x^{2} + x + 1\right)} + \frac{2}{3 \left(x - 1\right)}$$
    2           1 + 2*x    
---------- - --------------
3*(-1 + x)     /         2\
             3*\1 + x + x /
Combinatorics [src]
        1 + x        
---------------------
         /         2\
(-1 + x)*\1 + x + x /
$$\frac{x + 1}{\left(x - 1\right) \left(x^{2} + x + 1\right)}$$
(1 + x)/((-1 + x)*(1 + x + x^2))
Numerical answer [src]
(1.0 + x)/(-1.0 + x^3)
(1.0 + x)/(-1.0 + x^3)