General simplification
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$$- 8 p^{2} + 6 p + 1$$
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(- 8 p^{2} + 6 p\right) + 1$$
To do this, let's use the formula
$$a p^{2} + b p + c = a \left(m + p\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = -8$$
$$b = 6$$
$$c = 1$$
Then
$$m = - \frac{3}{8}$$
$$n = \frac{17}{8}$$
So,
$$\frac{17}{8} - 8 \left(p - \frac{3}{8}\right)^{2}$$
/ ____\ / ____\
| 3 \/ 17 | | 3 \/ 17 |
|p + - - + ------|*|p + - - - ------|
\ 8 8 / \ 8 8 /
$$\left(p + \left(- \frac{3}{8} + \frac{\sqrt{17}}{8}\right)\right) \left(p + \left(- \frac{\sqrt{17}}{8} - \frac{3}{8}\right)\right)$$
(p - 3/8 + sqrt(17)/8)*(p - 3/8 - sqrt(17)/8)
Rational denominator
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$$- 8 p^{2} + 6 p + 1$$
Assemble expression
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$$- 8 p^{2} + 6 p + 1$$
Combining rational expressions
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$$2 p \left(3 - 4 p\right) + 1$$