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How do you 2*x/(x^2-1) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
 2*x  
------
 2    
x  - 1
$$\frac{2 x}{x^{2} - 1}$$
(2*x)/(x^2 - 1)
Fraction decomposition [src]
1/(1 + x) + 1/(-1 + x)
$$\frac{1}{x + 1} + \frac{1}{x - 1}$$
  1       1   
----- + ------
1 + x   -1 + x
Combinatorics [src]
      2*x       
----------------
(1 + x)*(-1 + x)
$$\frac{2 x}{\left(x - 1\right) \left(x + 1\right)}$$
2*x/((1 + x)*(-1 + x))
Numerical answer [src]
2.0*x/(-1.0 + x^2)
2.0*x/(-1.0 + x^2)