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How do you (x^2-8*x+16)/(x-4) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
 2           
x  - 8*x + 16
-------------
    x - 4    
$$\frac{\left(x^{2} - 8 x\right) + 16}{x - 4}$$
(x^2 - 8*x + 16)/(x - 4)
General simplification [src]
-4 + x
$$x - 4$$
-4 + x
Fraction decomposition [src]
-4 + x
$$x - 4$$
-4 + x
Assemble expression [src]
      2      
16 + x  - 8*x
-------------
    -4 + x   
$$\frac{x^{2} - 8 x + 16}{x - 4}$$
(16 + x^2 - 8*x)/(-4 + x)
Powers [src]
      2      
16 + x  - 8*x
-------------
    -4 + x   
$$\frac{x^{2} - 8 x + 16}{x - 4}$$
(16 + x^2 - 8*x)/(-4 + x)
Trigonometric part [src]
      2      
16 + x  - 8*x
-------------
    -4 + x   
$$\frac{x^{2} - 8 x + 16}{x - 4}$$
(16 + x^2 - 8*x)/(-4 + x)
Combinatorics [src]
-4 + x
$$x - 4$$
-4 + x
Combining rational expressions [src]
16 + x*(-8 + x)
---------------
     -4 + x    
$$\frac{x \left(x - 8\right) + 16}{x - 4}$$
(16 + x*(-8 + x))/(-4 + x)
Numerical answer [src]
(16.0 + x^2 - 8.0*x)/(-4.0 + x)
(16.0 + x^2 - 8.0*x)/(-4.0 + x)
Common denominator [src]
-4 + x
$$x - 4$$
-4 + x
Rational denominator [src]
      2      
16 + x  - 8*x
-------------
    -4 + x   
$$\frac{x^{2} - 8 x + 16}{x - 4}$$
(16 + x^2 - 8*x)/(-4 + x)