Mister Exam
Other calculators
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How to use it?
- Factor squared:
- y^4+y^2+1
- x^2+x-2
- -y^2+4*y+3
- x^2-x+5
- Factor polynomial:
- x^10-1
- m^6+m^3
- x^2-4
- m^5-m^3
- Least common denominator:
- (z+z/q)*(z-z/q)
- (z-t)/(z+t)/(z-t)^2
- (z*sqrt(z^2-a^2))/2-(a^2*log(2*sqrt(z^2-a^2)+2*z))/2
- (z-(5*z)/z+1)/(z-4)/(z+1)
- How do you in partial fractions?:
- 2*(-1+(-1+x)/(2+x))/(2+x)^2
- (x+5)/(x^2+22*x+85)
- (5x^2+9x-2)/(x^2-5x-14)
- (4*a^3)^2*(3*b^3)^4/(12*a^2*b^4)^3
- Factor polynomial:
- x^2+x-2
- Graphing y =:
-
x^2+x-2
- Canonical form:
- x^2+x-2
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Identical expressions
- x^ two +x- two
- x squared plus x minus 2
- x to the power of two plus x minus two
- x2+x-2
- x²+x-2
- x to the power of 2+x-2
-
Similar expressions
- x^2+x+2
- x^2-x-2
Factor x^2+x-2 squared
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} + x\right) - 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = -2$$
Then
$$m = \frac{1}{2}$$
$$n = - \frac{9}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} - \frac{9}{4}$$
$$\left(x^{2} + x\right) - 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = -2$$
Then
$$m = \frac{1}{2}$$
$$n = - \frac{9}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} - \frac{9}{4}$$