Mister Exam
Other calculators
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How to use it?
- Factor squared:
- y^4-y^2+3
- y^4-y^2+12
- -y^4-y^2+15
- -y^4-y^2-11
- Factor polynomial:
- x^3-8
- x^2+x-6
- x^10-1
- m^2-n^2-m+n
- Least common denominator:
- (z/(z-1))+((z^2-1.0923*z)/(z^2-1.9061*z+0.9277))
- (z/x-z+x+z/z)/x/x^2-x*z^2
- z/(x+y)+x/(z+y)+y/(z+x)
- (z/x*x-3*x)/(z*z/3*x-9)
- How do you in partial fractions?:
- (z-2)/(6*z+(z-2)*(z-2))+(6/(z*z*z-8))
- 2*(-1+(-1+x)/(2+x))/(2+x)^2
- (x+5)/(x^2+22*x+85)
- 5*((x-4)/(x^2+4*x)-16/(16-x^2))/(1+4/x)
- Factor polynomial:
- x^2+x-2
- Graphing y =:
-
x^2+x-2
- Canonical form:
- x^2+x-2
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Identical expressions
- x^ two +x- two
- x squared plus x minus 2
- x to the power of two plus x minus two
- x2+x-2
- x²+x-2
- x to the power of 2+x-2
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Similar expressions
- x^2+x+2
- x^2-x-2
Factor x^2+x-2 squared
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} + x\right) - 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = -2$$
Then
$$m = \frac{1}{2}$$
$$n = - \frac{9}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} - \frac{9}{4}$$
$$\left(x^{2} + x\right) - 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = -2$$
Then
$$m = \frac{1}{2}$$
$$n = - \frac{9}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} - \frac{9}{4}$$