Mister Exam

Lang:

How to use it?
How do you in partial fractions?:
((4*x)^3*x^-11)/((x^-12)*(5*x^5))
y/(x-y)+x/(y-x)
sqrt((w^2*(-t^2)/(1+t^2*w^2))^2+(t*w/(1+t^2*w^2))^2)
1/(x^3+1)
Factor polynomial:
x^6-x^4*y^2-x^3+x^2*y
x^4-x^2+1
x^3+x^5
x^3+2*x
Least common denominator:
z^(((p-3)/(p^2+3*p))/(12/(9-p^2))*(3/(3*p-p^2)))
(z^2-4*z+16)/(16*z^2-1)*(4*z^2+z)/(z^3+64)-(z+4)/(4*z^2-z)/7/(z^2+4*z)-(20*z+13)/(7-28*z)
-(z^2+1)/(z-(-1-sqrt(3)*i)/2)^2+2*z/(z-(-1-sqrt(3)*i)/2)
y/(y+3)^2-y/(y^2)-9
Factor squared:
-y^4+y^2+1
y^4-y^2+1
-y^4+y^2-10
y^4+9*y^2+2
Derivative of:
1/(x^3+1)
Integral of d{x}:
1/(x^3+1)
Identical expressions
one /(x^ three + one)
1 divide by (x cubed plus 1)
one divide by (x to the power of three plus one)
1/(x3+1)
1/x3+1
1/(x³+1)
1/(x to the power of 3+1)
1/x^3+1
1 divide by (x^3+1)
Similar expressions
1/(x^3-1)

How do you 1/(x^3+1) in partial fractions?

You have entered [src]

  1   
------
 3    
x  + 1

\frac{1}{x^{3} + 1}

1/(x^3 + 1)

Fraction decomposition [src]

1/(3*(1 + x)) - (-2 + x)/(3*(1 + x^2 - x))

- \frac{x - 2}{3 \left(x^{2} - x + 1\right)} + \frac{1}{3 \left(x + 1\right)}

    1           -2 + x    
--------- - --------------
3*(1 + x)     /     2    \
            3*\1 + x  - x/

Numerical answer [src]

1/(1.0 + x^3)

1/(1.0 + x^3)

Combinatorics [src]

         1          
--------------------
        /     2    \
(1 + x)*\1 + x  - x/

\frac{1}{\left(x + 1\right) \left(x^{2} - x + 1\right)}

1/((1 + x)*(1 + x^2 - x))