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Factor polynomial:
p^3+8
x^2-x+5
x^2-y^2
x+x^2
Least common denominator:
4*((sin(8*x)/2+4*x)/8-sin(4*x)/2+x)
2/x+(3*x-2)/(x+1)
(234/(((7/20)*p+1)*(p+1)*((111/10)*p+1)))*((3/10)+10/p)
(z*z-1/2*z)/(z*z-z+1)*z/(z-1/2)
Factor squared:
y^4+y^2-15
-y^4+y^2+14
y^4+y^2+4
-y^4+y^2+11
How do you in partial fractions?:
y/(y+2)+(1/(4-y^2)-1/(4-4*y+y^2))/(2/(y-2)^2)
((y-9)/(y-8))*((y^2-64)/(y^2-16*y-64))
2*x/(x^2-1)
1/(cos(x)^2)
Identical expressions
p^ three + eight
p cubed plus 8
p to the power of three plus eight
p3+8
p³+8
p to the power of 3+8
Similar expressions
p^3-8

Expression simplification/ Factorization polynomials/ p^3+8

Factor polynomial p^3+8

The solution

You have entered [src]

 3    
p  + 8

$$p^{3} + 8$$

p^3 + 8

Factorization [src]

        /             ___\ /             ___\
(p + 2)*\p + -1 + I*\/ 3 /*\p + -1 - I*\/ 3 /

$$\left(p + 2\right) \left(p + \left(-1 + \sqrt{3} i\right)\right) \left(p + \left(-1 - \sqrt{3} i\right)\right)$$

((p + 2)*(p - 1 + i*sqrt(3)))*(p - 1 - i*sqrt(3))

Combinatorics [src]

        /     2      \
(2 + p)*\4 + p  - 2*p/

$$\left(p + 2\right) \left(p^{2} - 2 p + 4\right)$$

(2 + p)*(4 + p^2 - 2*p)

Numerical answer [src]

8.0 + p^3

8.0 + p^3