Mister Exam
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How to use it?
How do you in partial fractions?
:
(x^2+3*x-4)/(x+4)
((z^2+1)^2/(4*z^2))/(13+12*((z^2+1)/2*z*z))
2*(-1+4*x^2/(1+x^2))/(1+x^2)^2
(z+1)/(z+2)^3/(z-1)
Factor polynomial
:
x^6-x^4*y^2-x^3+x^2*y
x^4-x^2+1
x^6-x^4-x^2+1
x^2-x^2
Least common denominator
:
(z/40+1/20)*(z/40+4/5)*z
((z^2-49)/(2*z^2+1))*(((14*z+1)/(z-7))+((14*z-1)/(z+7)))
y/(y+3)^2-y/(y^2)-9
y/(y+2)+(1/(4-y^2)-1/(4-4*y+y^2))/(2/(y-2)^2)
Factor squared
:
y^4-y^2+10
y^4-y^2+1
y^4+9*y^2+2
-y^4+y^2+3
Integral of d{x}
:
1/(x^2)
Derivative of
:
1/(x^2)
Graphing y =
:
1/(x^2)
Identical expressions
one /(x^ two)
1 divide by (x squared )
one divide by (x to the power of two)
1/(x2)
1/x2
1/(x²)
1/(x to the power of 2)
1/x^2
1 divide by (x^2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2)
How do you 1/(x^2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 -- 2 x
$$\frac{1}{x^{2}}$$
1/(x^2)
Fraction decomposition
[src]
x^(-2)
$$\frac{1}{x^{2}}$$
1 -- 2 x
Numerical answer
[src]
x^(-2)
x^(-2)