Mister Exam
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How to use it?
How do you in partial fractions?
:
((4*x)^3*x^-11)/((x^-12)*(5*x^5))
(x^2+4*x+3)/(x+1)
3/(x^3+5)-9*x^3/(x^3+5)^2
2*x/(x^2+1)
Factor polynomial
:
x^4-x^2+1
x^9-3*x^6+3*x^3-16*x-9
x^3+x^4
x^3-x^2+x-1
Least common denominator
:
y/(y+2)+(1/(4-y^2)-1/(4-4*y+y^2))/(2/(y-2)^2)
x/sqrt(4-x*x)+2*x*(-1/sqrt(4-x*x)-(2+sqrt(4-x*x))/x^2)/(2+sqrt(4-x*x))
(x^4+5*x^3+15*x-9)/(x^6+3*x^4)+9/x^4
|x-3|/x-3+|x+1|/x+1
Factor squared
:
-y^4-9*y^2+7
y^4-y^2-10
-y^4-y^2-6
-y^4+y^2+4
Integral of d{x}
:
1/(x^2)
Derivative of
:
1/(x^2)
Graphing y =
:
1/(x^2)
Identical expressions
one /(x^ two)
1 divide by (x squared )
one divide by (x to the power of two)
1/(x2)
1/x2
1/(x²)
1/(x to the power of 2)
1/x^2
1 divide by (x^2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2)
How do you 1/(x^2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 -- 2 x
$$\frac{1}{x^{2}}$$
1/(x^2)
Fraction decomposition
[src]
x^(-2)
$$\frac{1}{x^{2}}$$
1 -- 2 x
Numerical answer
[src]
x^(-2)
x^(-2)