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How to use it?
How do you in partial fractions?
:
((z^2-z)/(z^2-9))^-1/(z^2-3*z)/(z-1)
x/(x^3-3x+2)
(x^2-2*x+1)/(x-1)
(x^2+1)/(x-1)
Factor polynomial
:
x^3*c^2-x^3*d^2
x^3+5*x^2+7*x+3
z^3+3*z^2+4*z+12-0
x^3-4
Least common denominator
:
1/(3*sqrt(1-x^2/9))
(z/b-b/z)*6*z*b/(z+b)
(a+1/a+2)/a+1
(z*(z^2+6*z+1)-(4*z*(z+1)))/(z-1)^3+z*(z-1)/(z+1)^3
Factor squared
:
x^2+x+2
y^4+y^2+3
-y^4+y^2+11
-y^4-y^2-6
Integral of d{x}
:
1/(x^2)
Graphing y =
:
1/(x^2)
Derivative of
:
1/(x^2)
Identical expressions
one /(x^ two)
1 divide by (x squared )
one divide by (x to the power of two)
1/(x2)
1/x2
1/(x²)
1/(x to the power of 2)
1/x^2
1 divide by (x^2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2)
How do you 1/(x^2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 -- 2 x
$$\frac{1}{x^{2}}$$
1/(x^2)
Fraction decomposition
[src]
x^(-2)
$$\frac{1}{x^{2}}$$
1 -- 2 x
Numerical answer
[src]
x^(-2)
x^(-2)