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How to use it?
How do you in partial fractions?
:
(5x^2+9x-2)/(x^2-5x-14)
b^9*b^7*b^2/(b^3*b^(1^9)*b^8)
1/(x^2)
((z^2-z)/(z^2-9))^-1/(z^2-3*z)/(z-1)
Factor polynomial
:
z^3+3*z^2+4*z+12-0
x^3-4
x^2-6*y+9*y^2
7*x*y/47+x^5+654+2^4*t^4
Least common denominator
:
(z*(z^2+6*z+1)-(4*z*(z+1)))/(z-1)^3+z*(z-1)/(z+1)^3
(pi*a^2+pi/4)/(pi*a^2+pi/2)
atan(tan(f)*sqrt(a^2-1)/a)/sqrt(a^2-1)
1/(3*sqrt(1-x^2/9))
Factor squared
:
y^4-y^2+4
x^2+x+2
x^4+2*x^2-8
x^2-3*x+2
Graphing y =
:
1/(x^2)
Integral of d{x}
:
1/(x^2)
Derivative of
:
1/(x^2)
Identical expressions
one /(x^ two)
1 divide by (x squared )
one divide by (x to the power of two)
1/(x2)
1/x2
1/(x²)
1/(x to the power of 2)
1/x^2
1 divide by (x^2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2)
How do you 1/(x^2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 -- 2 x
$$\frac{1}{x^{2}}$$
1/(x^2)
Fraction decomposition
[src]
x^(-2)
$$\frac{1}{x^{2}}$$
1 -- 2 x
Numerical answer
[src]
x^(-2)
x^(-2)