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How to use it?
How do you in partial fractions?
:
(5x^2+9x-2)/(x^2-5x-14)
(x^2+1)/(x-1)
1/(x^2)
b^9*b^7*b^2/(b^3*b^(1^9)*b^8)
Factor polynomial
:
m^5-m^3
x^2-x+5
x^3-1^3+3^3-x^3
-x^2+x
Least common denominator
:
(pi*a^2+pi/4)/(pi*a^2+pi/2)
(z/b-b/z)*6*z*b/(z+b)
y^(1/2)/(y^(1/2)+4)+4*y^(1/2)/(y-16)
1/(3*sqrt(1-x^2/9))
Factor squared
:
y^4-y^2+4
y^4+y^2-2
-y^4+7*y^2+3
y^4-y^2+15
Graphing y =
:
1/(x^2)
Integral of d{x}
:
1/(x^2)
Derivative of
:
1/(x^2)
Identical expressions
one /(x^ two)
1 divide by (x squared )
one divide by (x to the power of two)
1/(x2)
1/x2
1/(x²)
1/(x to the power of 2)
1/x^2
1 divide by (x^2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2)
How do you 1/(x^2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 -- 2 x
$$\frac{1}{x^{2}}$$
1/(x^2)
Fraction decomposition
[src]
x^(-2)
$$\frac{1}{x^{2}}$$
1 -- 2 x
Numerical answer
[src]
x^(-2)
x^(-2)