Mister Exam

Lang:

How to use it?
How do you in partial fractions?:
(234/(((7/20)*p+1)*(p+1)*((111/10)*p+1)))*((3/10)+10/p)
(z-(5*z)/z+1)/(z-4)/(z+1)
1/(1+x^2/3)
(x^2-5*x+6)/(x-3)
Factor polynomial:
y^3+y^5
x^3-x
x1^2+x2^2
x^3+7*x^2+15*x+9
Least common denominator:
sqrt(4/x+1)*x+2*log(sqrt(4/x+1)+1)-2*log(sqrt(4/x+1)-1)
(a-3+18/a+3)/a^2+9/a^2+6*a+9/a-3
5*(2-2/x^2)*cos(2*x+2/x)
(2*a+b)/(a^2-b^2)+1/(a+b)
Factor squared:
y^4+y^2-3
y^4+y^2+4
y^4-12*y^2+7
y^2+4*y-3
Least common denominator:
(z-(5*z)/z+1)/(z-4)/(z+1)
Identical expressions
(z-(five *z)/z+ one)/(z- four)/(z+ one)
(z minus (5 multiply by z) divide by z plus 1) divide by (z minus 4) divide by (z plus 1)
(z minus (five multiply by z) divide by z plus one) divide by (z minus four) divide by (z plus one)
(z-(5z)/z+1)/(z-4)/(z+1)
z-5z/z+1/z-4/z+1
(z-(5*z) divide by z+1) divide by (z-4) divide by (z+1)
Similar expressions
(z+(5*z)/z+1)/(z-4)/(z+1)
(z-(5*z)/z-1)/(z-4)/(z+1)
(z-(5*z)/z+1)/(z+4)/(z+1)
(z-(5*z)/z+1)/(z-4)/(z-1)

How do you (z-(5*z)/z+1)/(z-4)/(z+1) in partial fractions?

You have entered [src]

/    5*z    \
|z - --- + 1|
|     z     |
|-----------|
\   z - 4   /
-------------
    z + 1

$$\frac{\frac{1}{z - 4} \left(\left(z - \frac{5 z}{z}\right) + 1\right)}{z + 1}$$

((z - 5*z/z + 1)/(z - 4))/(z + 1)

General simplification [src]

  1  
-----
1 + z

$$\frac{1}{z + 1}$$

1/(1 + z)

Fraction decomposition [src]

1/(1 + z)

$$\frac{1}{z + 1}$$

  1  
-----
1 + z

Common denominator [src]

  1  
-----
1 + z

$$\frac{1}{z + 1}$$

1/(1 + z)

Trigonometric part [src]

  1  
-----
1 + z

$$\frac{1}{z + 1}$$

1/(1 + z)

Powers [src]

  1  
-----
1 + z

$$\frac{1}{z + 1}$$

1/(1 + z)

Combinatorics [src]

  1  
-----
1 + z

$$\frac{1}{z + 1}$$

1/(1 + z)

Combining rational expressions [src]

  1  
-----
1 + z

$$\frac{1}{z + 1}$$

1/(1 + z)

Numerical answer [src]

1/(1.0 + z)

1/(1.0 + z)

Rational denominator [src]

      2           
     z  - 4*z     
------------------
z*(1 + z)*(-4 + z)

$$\frac{z^{2} - 4 z}{z \left(z - 4\right) \left(z + 1\right)}$$

(z^2 - 4*z)/(z*(1 + z)*(-4 + z))

Assemble expression [src]

  1  
-----
1 + z

$$\frac{1}{z + 1}$$

1/(1 + z)